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3 years ago

A grocer can buy strawberries for $1.38 per pound

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

<h3>Answer: 175 pounds</h3>

Work Shown:

x = number of pounds of strawberries purchased

1.38x = cost of buying those x pounds of strawberries, at $1.38 a pound

1.38x = 241.50

x = (241.50)/(1.38)

x = 175

As a check,

1.38*x = 1.38*175 = 241.50

which confirms the answer

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Convert 1,230 minutes to hours.

4vir4ik [10]

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3 years ago

Read 2 more answers

Select the graph for the solution of the open sentence. Click until the correct graph appears. 2|x| + 1 < 5

Paul [167]

Answer:

The correct answer is x < 2 or x > -2. The graph would be a line between -2 and 2 with an open circle on both.

Step-by-step explanation:

To solve, first solve the equation for the absolute value portion of the equation.

2|x| + 1 < 5

2|x| < 4

|x| < 2

Now since there is an absolute value around it, we have to complete it for the positive and negative versions.

x < 2 OR x > -2

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4 years ago

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Lady_Fox [76]

I hope this helps you

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4 years ago

How many expressions are equivalent to 3/4

Elanso [62]

Answer:

9/12 and 6/8

Step-by-step explanation:

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3 years ago

A computer consulting firm presently has bids out on three projects. Let Ai = {awarded project i}, for i = 1, 2, 3, and suppose

Karo-lina-s [1.5K]

Step-by-step explanation:

The data below is what was provided in the question and it is what I solved the question with

P(A1) = 0.23

P(A2) = 0.25

P(A3) = 0.29

P(A1 n A2 ) = 0.09

P(A1 n A3) = 0.11

P(A2 n A3) = 0.07

P(A1 n A2 n A3) = 0.02

P(A2|A1) = P(A1 n A2)/P(A1)

= 0.09/0.23

= 0.3913

We have 39.13% confidence that event A2 will occur given that event A1 already occured

b.)

P(A3 n A3|A1) = P(A2 n A3)n A1)/P(A1)

= 0.02/0.23

= 0.08695

We have about 8.7% chance of events A2 and A3 occuring given that A1 already occured.

P(A2 u A3|A1)

= P(A1 n A2)u(A1 n A3)/P(A1)

= P( A1 n A2) + P(A1 n A3) - P(A1 n A2 n A3) / P(A1)

= (0.09+0.11-0.02)/0.23

= 0.18/0.23

= 0.7826

We have 78.26% chance of A2 or A3 happening given that A1 has already occured.

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3 years ago