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3 years ago

Uggh i hate myself feeling lost help

Mathematics

2 answers:

jasenka [17]3 years ago

7 0

Answer:

Why. And Girl if you ever need help. Let us know. Ok

Step-by-step explanation:

Mila [183]3 years ago

5 0

Answer:

I'm sorry I hope you feel better in the future <3

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Liam invests $3,670 in a savings account at his local bank which gives 1.9% simple annual interest. He also invests $2,040 in an

IRISSAK [1]

Step-by-step explanation:

Given:

Investment P₁ = $3670
Investment P₂ = $2040
Rate of interest r₁ = 1.9% SI
Rate of interest r₂ = 5.5% SI
Time t = 5 years

Find amount of interest in both investments:

I₁ = P₁r₁t = $3670*(1.9/100)*5 = $348.65
I₂ = P₂r₂t = $2040*(5.5/100)*5 = $561.00

As we see the online savings account earns more interest and the difference is:

$561.00 - $348.65 = $212.35 ≈ $212

7 0

3 years ago

2x + 3y = -14 y = 6x + 22

Fudgin [204]

2x+3y = -14y = 6x+22
Simplify
3Y=-14y=4x+22
Subtract 3y
-17Y=4X+22

4 0

4 years ago

5x+20=57 how do I solved

Tema [17]

I hope this helps you 5x+20=57 5x=57-20 5x=37 x=37/5

3 0

4 years ago

Read 2 more answers

Factor the expression completely. 25x2-65x - 30

Anton [14]

Answer:

$\large\boxed{25x^2-65x-30=5(x+3)(5x-2)}$

Step-by-step explanation:

$25x^2-65x-30=5(5x^2-13x-6)\\\\=5(5x^2-15x+2x-6)=5\bigg(5x(x-3)+2(x-3)\bigg)\\\\=5(x-3)(5x+2)$

3 0

3 years ago

I need the answer ASAP! Please help me!

masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Determining the length of BC

From the diagram, it is clear that

The point B is located at (-8, 10) and point C is located at (8, 10)

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

Determining the length of CD

Given

C (8, 10)

D (2, -2)

The distance between C(8, 10) and D(2, -2)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}$

$=\sqrt{6^2+12^2}$

$=\sqrt{36+144}$

$=\sqrt{180}$

$=\sqrt{36\times 5}$

$=6\sqrt{5}$

Thus, the length of CD $=6\sqrt{5}$ units

Determining the length of ED

Given

E (-8, -4)

D (2, -2)

The distance between E(-8, -4) and D(2, -2)

$ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}$

$=\sqrt{10^2+2^2}$

$=\sqrt{100+4}$

$=\sqrt{104}$

$=\sqrt{26\times \:4}$

$=2\sqrt{26}$

Thus, the length of ED $=2\sqrt{26}$ units

Determining the length of EB

From the diagram, it is clear that

The point E is located at (-8, -4) and the point B is located at (-8, 10)

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

4 0

3 years ago