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damaskus [11]
3 years ago
6

=-

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

Step-by-step explanation:

f(x) = x² - 7x+5 and g(x) = - 4x

(fog) (x) = (-4x)² -7(-4x) +5

= 16x² +28x +5

(fog)(2) = 16(2)² +28(2) +5

= 64 +56 +5

= 125

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A line passes through (1,-1) and (3,5)
Goryan [66]

Answer:

y= 3/1x -4

Step-by-step explanation:

6 0
3 years ago
What are the zeros in the function f(x)=(2x+6)(x-4)
Shtirlitz [24]

Hello from MrBillDoesMath!

Answer:

x = -3, 4

Discussion:

The zeroes of f(x) are the x values where

2x + 6 = 0   =>  x = -3

and

x - 4 = 0   => x = 4

Thank you,

MrB

8 0
4 years ago
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Solve the inequality <br> Math question
Flura [38]

Answer:

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Step-by-step explanation:

x <u><</u> 7

4 0
3 years ago
After a late night of studying, Ebony decides to grab a latte before class so she can stay awake through her morning lecture. Sh
Rzqust [24]

Answer:

P(Same\ Bill) = \frac{1}{3}

P(Second

P(Both\ Even) = \frac{1}{9}

Pr(One\ Odd) = \frac{4}{9}

P(Sum < 10) = \frac{1}{3}

Step-by-step explanation:

Given

Bills: \$1, \$5, \$10

Selection = 2\ bills

The sample space is as follows:

This implies that we construct possible outcome that Ebony selects a bill, returns the bill and then select another.

This means that there are possibilities that the same bill is selected twice.

So, the sample space is as follows:

S = \{(1,1), (1,5), (1,10), (5,1), (5,5), (5,10), (10,1), (10,5), (10,10)\}

n(S) = 9

Solving (a): P(Same\ Bill)

This means that the first and second bill selected are the same.

The outcome of this are:

Same = \{(1,1),(5,5),(10,10)\}

n(Same\ Bill) = 3

The probability is:

P(Same\ Bill) = \frac{n(Same\ Bill)}{n(S)}

P(Same\ Bill) = \frac{3}{9}

P(Same\ Bill) = \frac{1}{3}

Solving (a): P(Second  < First\ Bill)

This means that the second bill selected is less than the first.

The outcome of this are:

Second < First = \{(1,5), (1,10), (5,10)\}

n(Second < First) = 3

The probability is:

P(Second

P(Second

P(Second

Solving (c): P(Both\ Even)

This means that the first and the second bill are even

The outcome of this are:

Both\ Even = \{(10,10)\}

n(Both\ Even) = 1

The probability is:

P(Both\ Even) = \frac{n(Both\ Even)}{n(S)}

P(Both\ Even) = \frac{1}{9}

Solving (e): P(Sum < 10)

This question has missing details.

The correct question is to determine the probability that, the sum of both bills is less than 10

The outcome of this are:

One\ Odd = \{(1,10), (5,10), (10,1), (10,5)\}

n(One\ Odd) = 4

The probability is:

Pr(One\ Odd) = \frac{n(One\ Odd)}{n(S)}

Pr(One\ Odd) = \frac{4}{9}

 

Solving (d): P(One\ Odd)

This question has missing details.

The correct question is to determine the probability that, exactly one of the bills is 0dd

The outcome of this are:

Sum < 10 = \{(1,1), (1,5), (5,1)\}

n(Sum < 10) = 3

The probability is:

P(Sum < 10) = \frac{n(Sum < 10)}{n(S)}

P(Sum < 10) = \frac{3}{9}

P(Sum < 10) = \frac{1}{3}

 

3 0
3 years ago
The population of the United States, u, is about one hundred thousand less than the population of India, i. Write and equation t
nata0808 [166]

Answer: u = i- 100,000

Step-by-step explanation:

Hi, to answer this question we have to write an equation with  the information given:

Population of the United States = u

Population of India = i

Since the population of the United States, u, is about one hundred thousand less than the population of India, i, we have to subtract 100,000 (one hundred thousand) to the population of India (i). That expression must be equal to the population of United States (u).

Mathematically speaking:

u = i- 100,000

Feel free to ask for more if needed or if you did not understand something.  

7 0
3 years ago
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