O points

Oduvanchick [21]

Answer:

Step-by-step explanation:

Definition : The expression that can have constants (like 4), variables (like x or y) and exponents (like the 2 in $y^{2}$ ), that can be combined using addition, subtraction, multiplication and division, but no division by a variable and a variable's exponents can only be 0,1,2,3,... etc. and it can't have an infinite number of terms.

1. 6 + p

Being p be a variable this equation is polynomial

2. x – 1

Since x-1 has variable and constant so according to definition it is a polynomial

3. 8x−z3

According to definition it is a polynomial

4 . $5x^{2}-x\sqrt{}$

Since has root so it is not a polynomial .

6 0

2 years ago

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Which of the following is the solution for 13x-5x+6=6+8x?

Vikentia [17]

The answer will help you.

13x−5x+6=6+8x

13x+−5x+6=6+8x

(13x+−5x)+(6)=8x+6

8x+6=8x+6

8x+6=8x+6

8x+6−8x=8x+6−8x

6=6

6−6=6−6

0=0

It has a real numbers are solutions.

And the answer is A.

5 0

2 years ago

Simple equation IS ALSO KNOWN HAS

antoniya [11.8K]

Answer:

linear equation.

Step-by-step explanation:

Please mark as brainliest

6 0

3 years ago

I’ll mark you brainliest!!!

notka56 [123]

Answer:
C. (1,18)
Explanation
If you don’t know how to find it, just plug in the values into the equation until they are equal to each other

3 0

3 years ago

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Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

2 years ago