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The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
brainly.com/question/13531044
The exercise is related to the Ratio Test for Convergence. The rules for this kind of test are given below.
<h3>What are the rules for Ratio Test for Convergence?</h3>
The rules are:
- If the limit is less than 1 when conducting the ratio test, your series is definitely convergent.
- The test is inconclusive if the limit is equal to 1.
- The series is divergent if the limit is greater than 1.
Using this knowledge, we are able to state that
- A is not conclusive.
- C's convergence is absolute.
- There is divergence with D and E.
- B and F appear to be employing the nth-term test. The nth-term involves determining the sequence's limit as it approaches infinity.
The nth-term test determines whether a series is divergent if the limit is bigger than 0, thus, both B and F are divergent series.
Please see the attached for the full question and the link below for more about Ratio Test for Convergence:
brainly.com/question/16618162
Answer:
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