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2 years ago

They need to make room for the 2022 model.

Mathematics

1 answer:

Elena-2011 [213]2 years ago

4 0

I don’t know I just need points lol

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18 1/2 -2^3•(4 1/3 + 6 4/6)

Lesechka [4]

Answer:

- (139/2)

Step-by-step explanation:

18 1/2 -2^3•(4 1/3 + 6 4/6)

= 37/2 - 8 .( 13/3 + 40/6)

= 37/2 - 8 x 11

=37/2 - 88

= - (139/2)

7 0

2 years ago

Help me please help me

ziro4ka [17]

Yes it’s a function

7 0

3 years ago

Read 2 more answers

a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di

Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

$\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}$

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

$\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}$

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

$\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}$

Thus, the total prototypes will cost around $60.75

7 0

1 year ago

Which could be the missing data item for the given set of data if the median of the complete data set is 15?

Gre4nikov [31]

Answer:

A: 16

Step-by-step explanation:

its in between

5 0

3 years ago

Drag each tile to the correct box. A data set that consists of many values can be summarized using the five-number summary. Arra

dimaraw [331]

Answer:

Minimum < Q1 < Median < Q3< Maximum

Step-by-step explanation:

Given

Minimum, Median, Maximum, Q3 and Q1

<em>See attachment for complete question</em>

Required

Order from least to greatest

In a dataset, the range is:

$Range = Maximum - Minimum$

This implies that, the minimum is the least and the maximum is the highest of the dataset

So, we have:

Minimum < < < < Maximum

The median is the middle item; So, the above becomes

Minimum < < Median < < Maximum

In a dataset, the IQR is:

$IQR = Q_3 - Q_1$

This implies that:

$Q_3 > Q_1$

So, we have:

Minimum < Q1 < Median < Q3< Maximum

6 0

3 years ago