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Makovka662 [10]
3 years ago
9

Solve for the value of c.

Mathematics
2 answers:
Artemon [7]3 years ago
6 0
Right angles = 90 degrees
8c - 5 + 6c - 3 = 90
14c - 8 = 90
14c = 98, c = 7

Solution: c = 7
Yuri [45]3 years ago
6 0

Step-by-step explanation:

(8c-5)°=(6c-3)°

8c°-5°=6c°-3°

8c°-6c°=-3°-5°

2c°=-8°

c°=-8/2

c°= -4

Substitute the value

{8(-4)-5}

-32-5

-37°

(6c-3)

{6(-4)-3}

-24-3

-27

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A poll of a random sample of people in Sweden found that about 75% favored government-supported health care. Researchers believe
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4 years ago
Factors of 42 <br> I need to know what factors make 42
vodomira [7]

<em>1 x 42</em>

<em>2 x 21</em>

<em>3 x 14</em>

<em>6 x 7</em>

Step-by-step explanation:

We need to find factors of 42.

Factors: <em>Two numbers when multiplied if give you the required number then those 2 numbers are factors o that number.</em>

So, Factors of 42 are:

<em>1 x 42</em>

<em>2 x 21</em>

<em>3 x 14</em>

<em>6 x 7</em>

Only these numbers when multiplied will give 42.

So, All these numbers are factors of 42

Keywords: factors of numbers

Learn more about factors of numbers at:

  • brainly.com/question/1414350
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#learnwithBrainly

3 0
3 years ago
The distribution of actual weights of 8-ounce wedges of cheddar cheese produced at a dairy is Normal with mean 8.1 ounces and st
Sonja [21]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=8.1, \frac{0.2}{\sqrt{10}}=0.063)

approximately Normal, mean 8.1, standard deviation 0.063.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable weights of 8-ounce wedges of cheddar cheese produced at a dairy. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =8.1,\sigma =0.2)

We take a sample of n=10 . That represent the sample size.

What can we say about the shape of the distribution of the sample mean?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=8.1, \frac{0.2}{\sqrt{10}}=0.063)

approximately Normal, mean 8.1, standard deviation 0.063.

3 0
4 years ago
Can someone please answer this I don’t understand!
Dovator [93]

The coordinates of X are (5, 11).

Solution:

Given points of the line segment are P(2, 2) and T(7, 17)  

Let X be the point that partitions the directed line segment PT in the ratio 3 : 2

Using section formula, we can find the coordinate of the point that partitions the line segment.

Section formula:

$X(x, y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=2, y_{1}=2, x_{2}=7, y_{2}=17 and m = 3, n =2

Substitute these in the section formula,

$X(x, y)=\left(\frac{3 \times 7+2 \times 2}{3+2}, \frac{3 \times 17+2 \times 2}{3+2}\right)

            $=\left(\frac{21+4}{5}, \frac{51+4}{5}\right)

           $=\left(\frac{25}{5}, \frac{55}{5}\right)

           =(5, 11)

X(x, y) = (5, 11)

The coordinates of X are (5, 11).

6 0
3 years ago
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