During anaphase 1 chromosomes in the homologous pair moves to the opposite poles.
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Explanation:</u></h3>
The chromosomes that are having their pairs with similar length, position of centromere and staining pattern refers to the homologous chromosomes. These chromosomes have genes with the corresponding loci. One of these chromosomes will be inherited from the father and the other will be inherited from the mother.
The chromosomes in the pair gets attached to the fibers from the opposite poles. The chromatids that are sister will get attached to the fiber from the same poles. The centromere will not get divided during the anaphase 1 and thus the homologous chromosomes will move to the opposite poles. This causes the homologous chromosomes to get separated.
Explanation:
The rough ER, studded with millions of membrane bound ribosomes, is involved with the production, folding, quality control and despatch of some proteins. Smooth ER is largely associated with lipid (fat) manufacture and metabolism and steroid production hormone production.
The right answer is climate change.
Amphibians do not have the possibility of producing heat. Their activity depends on the environmental temperature and its fluctuations. For example, an average temperature increase of 1 ° C is likely to increase the metabolic expenditure of ectotherms by at least 10 to 30%. Global warming has or will have a significant impact on populations and their ability to adapt according to the evolutionary history of species.
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823