1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eddi Din [679]
3 years ago
7

Expand (x-2)^7 using binomial theorem

Mathematics
1 answer:
Nastasia [14]3 years ago
5 0

Answer:

x^7-14x^6+84x^5-280x^4+560x^3-672x^2+448x^2-128

Step-by-step explanation:

ends are x^7 and 120^7, and use the therom in the middle

You might be interested in
Find the exact length of the curve. y2 = 4(x + 1)3, 0 ≤ x ≤ 1, y > 0
mylen [45]
We can find this using the formula: L= ∫√1+ (y')² dx

First we want to solve for y by taking the 1/2 power of both sides:

y=(4(x+1)³)^1/2
y=2(x+1)^3/2

Now, we can take the derivative using the chain rule:

y'=3(x+1)^1/2

We can then square this, so it can be plugged directly into the formula:

(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9

We can then plug this into the formula:

L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765

The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
6 0
3 years ago
Which of the following is equal to the expression below?
aliina [53]

(8 x 320)^1/3

(2560)^1/3

(64*40)^1/3

64^1/3   *40^1/3

4 * (8^1/3) * 5^1/3

4 * 2 * 5^1/3

8 *5^1/3

None of your choices are written correctly

6 0
3 years ago
Read 2 more answers
Simplify the expression. 5(3f – 8g) 2g
SCORPION-xisa [38]
5 (3f-8g) 2g
*distribute the 5
15f-40g×2g
(im assuming its multiplication since there are no signs that say otherwise)
15f-80g
4 0
3 years ago
Read 2 more answers
A corporation purchased 1,000 shares of its own $5 par common stock at $10 and subsequently sold 500 of the shares at $17. What
zaharov [31]

The amount credited to paid in capital - treasury stock is $3,500.

<h3><u>Capital-treasury stocks</u></h3>

To determine what is the amount credited to paid in capital - treasury stock, the following calculation must be performed:

  • 1000 x 5 - 500 x 17 = X
  • 5000 - 8500 = X
  • -3500 = X

Therefore, the amount credited to paid in capital - treasury stock is $3,500.

Learn more about capital - treasury stocks in brainly.com/question/25715888

4 0
2 years ago
Consider the inequalities
Fantom [35]

Answer:

The line with be duchess with shading below.

None of the above

Step-by-step explanation:

The correct inequality expression is;

y < 2x+3

Note that the inequality sign between the expressions is the one that will determine the nature of the line.

Since the sign is not containing the "equal to" sign this means that the line will be broken(duchess).

Since it is "less than", the shading will be below the line.

Considering the given option, None of the option is correct

8 0
3 years ago
Other questions:
  • How do you get rid of a power in an equation?
    6·1 answer
  • a student achieved the following grades on his tests :87,95 ,76 and 88 percent . he wants 85 percent or better overall . what gr
    15·2 answers
  • Suppose a and b are integers. How many solutions are there to the equation ab = 2a + 3b?
    7·1 answer
  • 2 pounds equals how many onces
    10·2 answers
  • FORM A CUBIC POLYNOMIAL WHOSE ZEROS ARE -3,-1 AND 2
    8·1 answer
  • How do you check the answer of -6 = x/3
    5·1 answer
  • Will give Brainliest! if right!
    11·2 answers
  • Solve
    9·1 answer
  • What is the fully factored form of the expression 45x²y2 + 18x3
    8·1 answer
  • The two-way table below shows the number of students in a school who like mathematics and/or physics: Like Mathematics Do Not Li
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!