2(a+3)+3(2a-1)
=2a+6+6a-3
=8a+3
False, that is not greater than
Answer:
x1=2 and x2 =-3/2
Step-by-step explanation:
2x^2-x-6=0 (quvadratic equation)
a=2, b=-1, c=-6
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-(-1)+sqrt((-1)^2 - 4*2*(-6)))/2*2
x1 =(1+sqrt (1+48))/4
x1= (1+sqrt(49))/4
x1 =(1+7)/4
x1=8/4
x1=2
x2=(-b-sqrt(b^2-4ac))/2a
x2=(1-7)/4
x2=-6/4
x2=-3/2