So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
The price elasticities of demand of sugar-free gummy bears and of ordinary gummy bears is -0.8 and -2.3 respectively.
<h3>How to calculate price elasticity</h3>
Change in price of gummy bears = $2. 60 to $3
Elasticity of demand of sugar-free gummy bears =
[(273-379 / (273+379)/2] ÷ [(3.00-2.60)/(3.00+2.60) / 2]
= [-18/166] / [0.4/2.8]
= -0.10843373493975 / 0.14285714285714
= - 0.75903614457826
Approximately, -0.8
Elasticity of demand of regular gummy bears:
Sugar free = [(273-379) / (273+379)/2] ÷ (3.00 +2.60) / 2]
= [-106/326] / [0.4/2.8]
= -0.32515337423312 / 0.14285714285714
= -2.2760736196318
Approximately, -2.3
Learn more about price elasticity:
brainly.com/question/24961010