Answer:
y-1 = 5(x+8)
Step-by-step explanation:
The standard equation of a line in point slope form is expressed as;
y-y0 = m(x-x0)
m is the slope
(x0, y0) is the point
Given
Slope m = 5 (assumed value)
Point (-8,1)
Substitute the given data's into the formula
y -1 = 5(x-(-8))
y-1 = 5(x+8)
Hence the required equation is y-1 = 5(x+8)
This question is incomplete because it does not show us the diagram. Find attached to this answer, the appropriate diagram
Question
What is the height of the shape formed by the sectors shown below? A circle is cut into 8 equal sections. The sections are arranged into the shape of a parallelogram with a base of pi r and height of question mark.
a. r
b. d
c. pi times r
d Pi times d
Answer:
a. r
Step-by-step explanation:
In the diagram shown, we can see the sections are divided into 8 and each has a radius of r
The 8 sections from the circle is used to form the a parallelogram.
If we take a look at the diagram of the parallelogram closely, we can see definitely that it still showing the divided 8 equal sections using to form it.
Hence, the height of the parallelogram = the radius of the circle.
Therefore, height of the shape formed by the sectors is r
The solution to this question is x=9
1) Diagonals of a rectangle bisect each other, so AW=13.
2) Since diagonals of a rectangle are congruent, AC=BD. Then, since diagonals of a rectangle bisect each other, DW=13.
3) Diagonals of a rectangle are congruent, so BD=26.
4) Opposite sides of a rectangle are congruent, so AD=10.
5) Using the Pythagorean theorem, BA=24.
Step-by-step explanation:
remember, the sum of all angles in a triangle is always 180°.
and the sum of all angles around one point at one side of a line is also airways 180° (because you can imagine that point to be the center of a circle, and the line would cut that circle in half = 180° for every half).
in the triangle LKM we know 2 angles already :
angle 1 = 44°
angle K = 90° (right angle).
so, angle 2 = 180 - 90 - 44 = 46°
and so, angle 5 = 180 - 46 = 134°.
as the angles around point L on line KL are the angles 2 and 5.
angle 5 = 134°