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Oksana_A [137]
3 years ago
8

Describe your microsoft word skills that need to be improved upon the most.​

Computers and Technology
1 answer:
Ilya [14]3 years ago
5 0
Shortcuts & Formatting Tricks
Mail Merge
Table of Contents
Compare Documents
Track Changes
Using Synonyms
Presenting Tabular data
Managing Header & Footer
Adding Pictures at right position
Automating tasks through Macros
572 viewsView 4 Upvoters
Related Questions (More Answers Below)
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Qbasic program to accept 10 numbers and to find their sum. <br>​
sesenic [268]

Answer:

the answer is 5

Explanation:

6 0
3 years ago
class student_record { public: int age; string name; double gpa; }; Implement a void function that has five formal parameters: a
Setler79 [48]

Answer:

void delete_record(student_record *arr, int &size, int age, string name, double gpa) {

int index = -1;

if (arr != NULL && size > 0) {

for (int i = 0; i < size; ++i) {

if (arr[i].age == age && arr[i].name == name && arr[i].gpa == gpa) {

index = i;

break;

}

}

}

if (index != -1) {

for (int i = index; i < size - 1; ++i) {

arr[i] = arr[i + 1];

}

size--;

}

}

8 0
3 years ago
Lesser-known ideas and interpretations of common knowledge need to be documented. true or false.
Tresset [83]
False. As it is common knowledge, it is unnecessary for it to be documented.
7 0
2 years ago
In this assignment, you will create a flashcard app for teaching addition and multiplication. The student will choose the type o
Anna11 [10]

Answer:

See explaination

Explanation:

import java.util.*;

import java.lang.Math;

public class Main

{

public static double getRandomDoubleBetweenRange (double min, double max)

{

double x = (Math.random () * ((max - min) + 1)) + min;

return x;

}

public static void main (String[]args)

{

int option, number_of_problems, correct_answer;

double max_operand, average =

0, user_answer, sum, first_number, second_number, multiply,

sum_or_multiply;

Scanner user_input = new Scanner (System.in);

do

{

System.out.println

("Choose the type of problem: \n1. Addition \n2. Multiplication \n3. Mixed \n4. Quit");

option = user_input.nextInt ();

switch (option)

{

case 1:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum = first_number + second_number;

if (sum == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

sum);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 2:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

multiply = first_number * second_number;

if (multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

multiply);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 3:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 1; i <= number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

if (i % 2 == 1)

{

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number + second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

else

{

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number * second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 4:

System.out.println ("Thanks for playing.");

break;

default:

System.out.println ("Please choose a valid option");

break;

}

}

while (option != 4);

}

}

3 0
3 years ago
Write a static method middleValue that takes three int parameters, and returns a int . It should return the middle value of the
anygoal [31]

We use if-else structure to check the each possible scenario and return the median accordingly in the middleValue() method. The main is also provided so that you can test the method.

Comments are used to explain the each line.

You may see the output in the attachment.

public class Main

{

public static void main(String[] args) {

   

    //call the method for different scenarios

    System.out.println(middleValue(1, 2, 3));

    System.out.println(middleValue(1, 3, 2));

    System.out.println(middleValue(2, 1, 3));

    System.out.println(middleValue(2, 3, 1));

    System.out.println(middleValue(3, 1, 2));

    System.out.println(middleValue(3, 2, 1));

 

}

       //method that takes three int and returns an int

public static int middleValue(int n1, int n2, int n3) {

    //set the median as n1

    int median = n1;

   

    //check the situation where the n1 is the highest

    //if n2 is greater than n2 -> n1 > n2 > n3

    //if not -> n1 > n3 > n2

    if(n1 > n2 && n1 > n3){

        if(n2 > n3)

            median = n2;

        else

            median = n3;

    }

   

    //check the situation where the n2 is the highest

    //if n3 is greater than n1 -> n2 > n3 > n1

    //if not -> n2 > n1 > n3

    //note that we set the median as n1 by default, that is why there is no else part

    else if(n2 > n1 && n2 > n3){

        if(n3 > n1)

            median = n3;

    }

   

    //otherwise, n3 is the highest

    //if n2 is greater than n1 -> n3 > n2 > n1

    //if not -> n3 > n1 > n2

    //note that we set the median as n1 by default, that is why there is no else part

    else{

        if(n2 > n1)

            median = n2;

    }

   

    return median;

}

}

You may see another if-else question at:

brainly.com/question/13428325

6 0
2 years ago
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