Answer:
Required code is given below:
Explanation:
def add_to_dict(dictt, key,value):
if key in dictt.keys():
print("Error. Key already exists.")
else:
dictt[key]=value
return dictt
def remove_from_dict(dictt,key):
try:
dictt[key]
dictt.pop(key, None)
return dictt
except KeyError:
print("No such key exists in the dictionary.")
def find_key(dictt,key):
try:
value=dictt[key]
print("Value: ", value)
except KeyError:
print("Key not found.")
Answer:
F and H
Explanation:
Cloud stores and saves all your information and a hard drive you can carry around
If anyone who knows more about this can correct me or say that im correct that would be of much help.
Answer:
Explanation:
The following code is written in Python. It creates a for loop that iterates 10 times, asking the user for a number every time. It then checks if the number is inside the numArray. If it is not, then it adds it to the array, if it is then it skips to the next iteration. Finally, it prints the number of distinct numbers and the list of numbers.
numArray = []
for x in range(10):
num = input("Enter a number")
if int(num) not in numArray:
numArray.append(int(num))
print("Number of Distince: " + str(len(numArray)))
for num in numArray:
print(str(num), end = " ")
Answer: Click a layer in the Layers panel. To select multiple contiguous layers, click the first layer and then Shift-click the last layer. To select multiple noncontiguous layers, Ctrl-click (Windows) or Command-click (Mac OS) them in the Layers panel.
Explanation:
