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nignag [31]
3 years ago
10

How can probabilities be used to make predictions?

Mathematics
2 answers:
natima [27]3 years ago
5 0

Answer:

multiply the experimental probability by the number of trials to get a prediction

Step-by-step explanation:

i looked on quizlet...

Bas_tet [7]3 years ago
4 0

Answer:

Probabilities are by how likely something is to happen, the weather is a great example, they use probabilities to find what the chance is for example like rain or snow, depending on those chance they come out with their predictions at which time to expect it to happen.

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Using the function f(x) = 2x + 7 find the following: (show your work)<br><br> f(2)<br><br><br> f(7)
denpristay [2]
Replace the x with 2: f(2)=2*2+7=4+7=11
replace the x with 7: f(7)=2*7+7=14+7=21
8 0
3 years ago
Read 2 more answers
Create write an expression that simplifies to 2a + 14 using the distributive property
geniusboy [140]

Answer:

2 ( a + 7)

Step-by-step explanation:

2a + 14

both 2a and 14 are divisible by 2

2a/a = a

14/2 = 7

2( a + 7) = 2a + 14

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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3 years ago
The national mean annual salary for a school administrator is $90,00 a year (The Cincinnati Enquirer, April 7, 2012). A school o
timurjin [86]

Answer:

a) Null hypothesis:\mu = 90000  

Alternative hypothesis:\mu \neq 90000  

b) p_v =2*P(t_{(24)}  

c) If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

Step-by-step explanation:

1) Data given and notation  

77600 ,76000 ,90700 ,97200 ,90700 ,101800 ,78700 ,81300 ,84200 ,97600 ,

77500 ,75700 ,89400 ,84300 ,78700 ,84600 ,87700 ,103400 ,83800 ,101300

94700 ,69200 ,95400 ,61500 ,68800

We can calculate the sample mean and deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

The values obtained are:

\bar X=85272 represent the mean annual salary for the sample  

s=11039.23 represent the sample standard deviation for the sample  

n=25 sample size  

\mu_o =90000 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean salary differs from 90000, the system of hypothesis would be:  

Null hypothesis:\mu = 90000  

Alternative hypothesis:\mu \neq 90000  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{85272-90000}{\frac{11039.23}{\sqrt{25}}}=-2.141    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(24)}  

Part c: Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

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3 years ago
Trina, James, and Michael are training for a 10-kilometer race. After 30 minutes of a training run, Michael lead the group, and
Llana [10]

Answer:

1/3

Step-by-step explanation:

1/2 James' fraction of Michael

2/3 Trina's fraction of James

1/2 x 2/3 = 1/3

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3 years ago
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Thank you for the points
8 0
2 years ago
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