3 years ago

Solve the following equations putting them in slope intercept form. Then

Mathematics

1 answer:

asambeis [7]3 years ago

7 0

Answer:

1. slope is -1 and y intercept is 2

3. slope is -2 and y intercept is -4

2. slope is -4 and y intercept is 2

4. this is not a line - it is a parabola

Step-by-step explanation:

1. -4y = 4x -8

y = -x + 2

3. 4y = -8x -16

y = -2x - 4

2. y = -4x + 2

4. y - 14 = -3x^2 -16x

y = 3x^2 - 16x + 4

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Carter has one 20$ bill, one 10$bill, four 5$ bills and two 1$ bill,Aubrey has two 10$bills ,five 5$ bills and seven 1$ bills .w

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Segment FG begins at point F(-2, 4) and ends at point G (-2, -3). Segment FG is translated by (x, y) → (x – 3, y + 2) and then r

Mariana [72]

Answer:

The length of the segment F'G' is 7.

Step-by-step explanation:

From Linear Algebra we define reflection across the y-axis as follows:

$(x',y')=(-x, y)$ , $\forall\, x, y\in \mathbb{R}$ (Eq. 1)

In addition, we get this translation formula from the statement of the problem:

$(x',y') =(x-3,y+2)$ , $\forall \,x,y\in \mathbb{R}$ (Eq. 2)

Where:

$(x, y)$ - Original point, dimensionless.

$(x', y')$ - Transformed point, dimensionless.

If we know that $F(x,y) = (-2, 4)$ and $G(x,y) = (-2,-3)$ , then we proceed to make all needed operations:

Translation

$F''(x,y) = (-2-3,4+2)$

$F''(x,y) = (-5,6)$

$G''(x,y) = (-2-3,-3+2)$

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$G'(x,y) = (5,-1)$

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$F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}$

$F'G' = 7$

The length of the segment F'G' is 7.

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3 years ago

-3+x=4 solve this question

user100 [1]

Just add 3 to both sides
x = 7

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