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MrMuchimi
2 years ago
5

Population Bellingham, Washington, had an area of 25.4 mi? and a population

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
4 0

nothing yw listen to your teacher !

:)

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9 more than the product of 51 and the number t
ElenaW [278]
It is 60 because 51+9 is 60
7 0
3 years ago
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Give the values of a, b, and c needed to write the equation's general form. 2/3(x - 4)(x + 5) = 1
ale4655 [162]

The first step is to write this equation into general form. The general form of an equation is:

ax^2 + bx + c = 0

To make this equation to general form, you have to simplify the equation first.

2/3(x-4) (x+5) = 1

2/3 (x^2 + 5x – 4x – 20) = 1

2/3(x^2 + x -20) = 1

2/3x^2 + 2/3x – 40/3 = 1

2/3x^2 + 2/3x – 40/3 – 1 = 0

2/3x^2 +2/3x – 43/3 = 0

Therefore, a = 2/3 ; b = 2/3 ; c = -43/3   

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3 years ago
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Which linear inequality is represented by the graph?
pochemuha

Answer:

y>3x -1 is the right answer

3 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
A frame is 6in tall and 8 in wide. What if it was reduced to a width of 4in then how tall will it be
kkurt [141]

Answer:

  3 in

Step-by-step explanation:

Apparently, we are to assume that the height and width are proportional:

  height/width = (6 in)/(8 in) = (new height)/(4 in)

Multiplying by 4 in will tell us the new height:

  new height = (4 in)(6/8) = 3 in

The reduced frame will be 3 inches tall.

6 0
3 years ago
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