AB=48, DC=88
48+88=136
136÷2=68
Answer: LM=68
Remember that the length of the mid segment in a trapezoid is half the sum of the base lengths.
Answer:39%
Step-by-step explanation:
78/100÷2
78/100×1/2
=39
Let
x = the number of shorts bought
y = the number of t-shirts bought
A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10 (1)
Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2 (2)
Graph the equations y = -1.6x + 10 and x = 2.
The shaded region satisfies both inequalities.
Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.
Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
What is the question?????