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3 years ago

I NEED BIG TIME HELP PLEASE ANYONE

Mathematics

2 answers:

fiasKO [112]3 years ago

7 0

Answer:

Its B

Step-by-step explanation:

AlexFokin [52]3 years ago

6 0

Answer:

the answer would be B I took the quiz

Step-by-step explanation:

I took the quiz

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sveta [45]

Answer:

the answer is c

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3 years ago

Identify this coefficient 8x

galben [10]

Answer:

Step-by-step explanation:

The term 8x is a product (as is any term). It is the product of a constant coefficient (8) and a variable (x). The "coefficient" is the multiplier of the variable of interest, so is 8 in this term.

_____

The word "coefficient" is often used to refer to the constant multiplier in any term. For example, in the term 6xy, if we just ask for the coefficient, we are interested in the value 6.

On the other hand, if we ask for the coefficient of y in that term, we expect to be told it is <em>6x</em>. That is, the "coefficient" is the multiplier of the specified variable or constellation of variables.

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3 years ago

mrs. wilson placed the welcome mat shown below on her front door step. what is the area of her welcome mat in square feet?

I am Lyosha [343]

Answer:

12.56 square feet

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3 years ago

Help!! Would the answer be c??

Westkost [7]

The answer is a. jksksvw

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3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

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3 years ago