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3 years ago

Where is the point (7, -1-0) loacted on the coordinate plane?

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

Can u show a pic so I can help ?

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A bag contains 2 5/8 pounds of candy. If the candy is equally distributed to point

nirvana33 [79]

The correct answer is 3/8

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3 years ago

Negative four ninths minus two fifteenths'

shepuryov [24]

$negative \ four \ ninths \to -\frac{4}{9} \\\\ two \ fiftheenths \to\frac{2}{15} \\\\ -\frac{4}{9}^{(5}-\frac{2}{15}^{(3}= \\\\ =-\frac{20}{45}-\frac{6}{45}= \\\\ =\boxed{-\frac{26}{45}}$

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3 years ago

How do I find the value of x?

EleoNora [17]

Answer:

Since you're asking <em>how</em> to find the value of x, you can use cosine, since the triangle is a right triangle.

8 0

3 years ago

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The base of a solid oblique pyramid is an equilateral triangle with an edge length of s units.

Assoli18 [71]

Answer:

Option B is correct.i.e.,

Step-by-step explanation:

Given: Pyramid with equilateral triangle as base

Length of side of equilateral triangle = s unit

to find: height of equilateral triangle

Here we use a property of equilateral triangle.

Perpendicular from a vertex on a side and median of that side of a triangle is same in equilateral triangle.

All heights are of equal length. So, we just need to find one height or length of 1 altitude.

Figure of base triangle is attached

In Δ ABC

AB = BC = AC = s unit

AD is height

BD = $\frac{BC}{2}\:=\:\frac{s}{2}\:units$

Now, In Δ ABD

using pythagoras theorem

BD² + AD² = AB²

$(\frac{s}{2})^2+AD^2=s^2$

$\frac{s^2}{4}+AD^2=s^2$

$AD^2=s^2-\frac{s^2}{4}$

$AD^2=\frac{4s^2-s^2}{4}$

$AD^2=\frac{3s^2}{4}$

$AD=\sqrt{\frac{3s^2}{4}}$

$AD=\frac{\sqrt{3}s}{2}$

$AD=\frac{s}{2}\sqrt{3}$

Therefore, Option B is correct.i.e., $\frac{s}{2}\sqrt{3}$

4 0

3 years ago

Read 2 more answers

Select the correct answer.

lilavasa [31]

Answer:

Step-by-step explanation:

Given

- $\frac{1}{4}$ (12x + 8) ≤ - 2x + 11 ← distribute parenthesis on left side

- 3x - 2 ≤ - 2x + 11 ( add 3x to both sides )

- 2 ≤ x + 11 ( subtract 11 from both sides )

- 13 ≤ x , thus

x ≥ - 13

Since x can equal - 13 then a solid circle at - 13 represents the solution

Since x greater than - 13 then the arrow is facing to the right of - 13 on the number line.

Then the graph representing the solution is C

3 0

3 years ago