The edible fruit=fruit-seed
alright
vsphere=4/3pir^3
so if the volume is 100
of the seed
find r
times both sides by 3/4
divide both sides by pi
cube root both sides
![\sqrt[3]{\frac{75}{\pi}}= r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B75%7D%7B%5Cpi%7D%7D%3D%20r)
this is the seed radius
3 times of taht is the radius of the fruit
![3\sqrt[3]{\frac{75}{\pi}}](https://tex.z-dn.net/?f=3%5Csqrt%5B3%5D%7B%5Cfrac%7B75%7D%7B%5Cpi%7D%7D)
=radiusfruit
input into equation
use radius fruit for r
![V=\frac{4}{3}\pi (3\sqrt[3]{\frac{75}{\pi}})^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%283%5Csqrt%5B3%5D%7B%5Cfrac%7B75%7D%7B%5Cpi%7D%7D%29%5E3)
so the edible part is 2700-100=2600 cm³
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
you found $222 in your pocket
Step-by-step explanation:
Answer:
(x -3)² +(y -5)² = 36
Step-by-step explanation:
The center is on the vertical line halfway between the given vertical lines, so is at x=3. It is also on the horizontal line through the point (-3, 5), so is at y=5. The center is 9-3=6 from either tangent line, so this is the radius.
For center (h, k) and radius r, the circle's equation is ...
(x -h)² +(y -k)² = r²
For (h, k) = (3, 5) and r=6, the equation is ...
(x -3)² +(y -5)² = 36 . . . . . . . . does not match any choice written here
