Are the expressions 3n+4n+1+2n−3 and 9n−2 equivalent?
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Answer:
The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>
Step-by-step explanation:
Given:
Initial speed of debris is,
The height 'h' of the debris above the ground is given as:
As per question, . Therefore,
Rewriting the above equation into a standard quadratic equation and solving for 't', we get:
Using quadratic formula to solve for 't', we get:
Therefore, the debris will reach a height of 56 ft twice.
When time during the upward journey, the debris is at height of 56 ft.
Again after reaching maximum height, the debris falls back and at , the height is 56 ft.