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2 years ago

I need answers very quick my brain is smol

Mathematics

2 answers:

Yakvenalex [24]2 years ago

8 0

Exact form: x=-10/3
Mixed number form: x=3 1/3

zalisa [80]2 years ago

6 0

How are even supposed to work that out

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Which would best display the following data if you wanted to display the numbers which are outliers as well as the mean? [4, 1,

Serhud [2]

Arranging data in ascending order to identify the outlier and calculate the mean

Step-by-step explanation:

Given the data as: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arrange in ascending order

[1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is 32

Finding the mean;

Mean=sum of data set/number of data set

Sum= 1 + 3+ 4+ 4+ 9+ 10+ 12+ 15+ 16+ 18+ 32=124

Number of data set=11

Mean=124/11=11.27

Learn More

Outliers: brainly.com/question/12612191

Keywords: display,data, numbers,outliers,mean

#Learnwithbrainly

3 0

3 years ago

684,658 round to the nearest hundred thousand

OverLord2011 [107]

700,000 is the answer I believe

8 0

3 years ago

Read 2 more answers

In the circle above, FH and GJ are chords which intersect at point K. If FK = 3 mm, HK = 4 mm, and GK = 2 mm, what is the length

Svetach [21]

We have a formula for that( according to the Intersecting chords theorem)
$fk \times hk = gk \times jk$
3×4=2×jk
6=jk

6 0

3 years ago

What regular polygon has an interior angle of 156 degrees

icang [17]

Answer:

regular pentadecagon

Step-by-step explanation:

it has 15 sides

that is what matches the exterior angled sum property - 360degree

let me explain it

1 side = 180 - 156 = 24

360/24 = 15

mark me brainliest and thank me if you like the answer

4 0

2 years ago

What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?

xxMikexx [17]

We have been given an equation of hyperbola $\frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1$ . We are asked to find the center of hyperbola.

We know that standard equation of a vertical hyperbola is in form $\frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1$ , where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

$\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1$

Now we can see that value of k is $-3$ . Therefore, the vertex of given hyperbola will be at point $(6,-3)$ and option D is the correct choice.

6 0

3 years ago