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Nimfa-mama [501]
3 years ago
9

Use the quadratic formula to solve x2 – 5x - 2 = 0.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

• The quadratic formular is as below:

{ \boxed{ \rm{x =  \frac{ - b \pm \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

• Basing on our equation given, x² - 5x - 2 = 0;

  • a → 1
  • b → -5
  • c → -2

{ \rm{x =  \frac{ - ( - 5) \pm \sqrt{ {(  - 5)}^{2} - (4 \times 1 \times  - 2) } }{(2 \times 1)} }} \\  \\ { \rm{x =  \frac{5 \pm \sqrt{33} }{2} }}

• Therefore;

{ \boxed{ \rm{x =  \frac{5 +  \sqrt{33} }{2} }}}{ \rm{ \:  \: or \:  \: }}{ \boxed{ \rm{x =  \frac{5 -  \sqrt{33} }{2} }}} \\  \\ { \boxed{ \boxed{ \rm{x = 5.37 \:  \: or \:  \: - 0.37}}}}

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TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
borishaifa [10]

Answer:

<u>A. It would be needed 20 packets to transmit 30,000 bytes of information.</u>

<u>B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

<u>B. </u>How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

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3 years ago
In triangle ABC, angleACB is a right angle
viktelen [127]

Answer:

I think is 11.4

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6 0
4 years ago
Solve using substitution.<br> 4x – 7y = -18<br> x = 6
levacccp [35]

Answer:

6

Step-by-step explanation:

4(6) - 7y = -18

24 - 7y = -18

-7y= -42

y= 6

3 0
3 years ago
Read 2 more answers
Find f(2) if f(x) = (x 1)2.
Katyanochek1 [597]
I hope this helps you



x=2



f (2)=(2+1)^2=3^2=9
8 0
3 years ago
Read 2 more answers
Explain why the function of f(x)=4x^2+8x is neither even or odd
myrzilka [38]

Answer:

By putting x = -x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

Step-by-step explanation:

We need to explain why the function of f(x)=4x^2+8x is neither even or odd

First we will understand, when the function is even and odd

Even function:

<em>A function is even if f(-x) = f(x) </em>

Odd function:

<em>A function is odd if f(-x) = -f(x) </em>

So, if we get the above result by putting x = -x, then we can say that the function is even or odd.

If we don't get any of the above results then the function is neither even nor odd.

So, for the given function: f(x)=4x^2+8x

Put x = -x

f(x)=4x^2+8x\\Put x=-x\\f(-x)=4(-x)^2+8(-x)\\f(-x)=4x^2-8x

So, by putting x=-x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

6 0
3 years ago
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