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Nimfa-mama [501]
3 years ago
9

Use the quadratic formula to solve x2 – 5x - 2 = 0.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

• The quadratic formular is as below:

{ \boxed{ \rm{x =  \frac{ - b \pm \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

• Basing on our equation given, x² - 5x - 2 = 0;

  • a → 1
  • b → -5
  • c → -2

{ \rm{x =  \frac{ - ( - 5) \pm \sqrt{ {(  - 5)}^{2} - (4 \times 1 \times  - 2) } }{(2 \times 1)} }} \\  \\ { \rm{x =  \frac{5 \pm \sqrt{33} }{2} }}

• Therefore;

{ \boxed{ \rm{x =  \frac{5 +  \sqrt{33} }{2} }}}{ \rm{ \:  \: or \:  \: }}{ \boxed{ \rm{x =  \frac{5 -  \sqrt{33} }{2} }}} \\  \\ { \boxed{ \boxed{ \rm{x = 5.37 \:  \: or \:  \: - 0.37}}}}

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Answer:

True.

Step-by-step explanation:

Since volume of any 3-D figure is length*width*height.

<u>Given</u>

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Answer:

x intercept is (-\frac{5}{3} , 0)

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Step-by-step explanation:

1.) turn the equation into slope intercept form, so...

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2.)When finding the x-intercept, then plug y=0 and solve for x.

(0)= -\frac{3x}{2} +\frac{5}{2} \\(\frac{2}{3}) -\frac{5}{2} =-\frac{3x}{2} (\frac{2}{3} )\\-\frac{5}{3} =x

3.) When finding the y-intercept, plug x=0 and solve for x.

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n the graph below determine how many real solutions the quadratic function has, and state them, if applicable. List solutions in
IRINA_888 [86]

Answer:

There are no real solutions.

Step-by-step explanation:

There are 3 options.

2 real solutions: This happens if in the graph, each arm intersects the x-axis, this means that there are two different values of x such that the equation:

a*x^2 + b*x + c

is equal to zero.

Another way to see this, is if the determinant:

b^2 - 4*a*c

is larger than zero.

1 real solution: This happens when the vertex of the graph intersects the x-axis. This means that there is a single value of x such that:

a*x^2 + b*x + c

is equal to zero.

Another way to see this is if the determinant:

b^2 - 4*a*c

is larger equal zero.

No real solution: if in the graph we can not see any intersection of the x-axis, then we do not have real solutions (only complex ones).

Another way to see this is if the determinant:

b^2 - 4*a*c

is smaller than zero.

Now that we know this, let's look at the graph.

We can see that the vertex is below the x-axis, and the arms of the graph go downwards. So the arms will never intersect the x-axis (and neither the vertex).

So the graph does not intersect the x-axis at any point, which means that there are no real solutions for the quadratic equation.

The correct answer would be "none"

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3 years ago
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Ksju [112]

-9 - 5x in word form would be:

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Hope this helps you

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3 years ago
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