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2 years ago

13

F(105)=105/7 use the following functions to find f(105)

1 answer:

sashaice [31]2 years ago

4 0

Answer:

F(105) = 15

Step-by-step explanation:

105 ÷ 7 = 15

Hope this helps!

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In the diagram below, AB is parallel to CD. What is the value of x?

lara31 [8.8K]

Answer:

x = 72

Step-by-step explanation:

angles x and 72° are corresponding angles and are congruent , then

x = 72

3 0

2 years ago

In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm

tangare [24]

Answer:

$AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm$

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

$AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm$

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

$\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD$

Consider right triangle CAH.By the Pythagorean theorem,

$CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8$

The length cannot be negative, so CD=8 cm and

$CA=\sqrt{3}CD=8\sqrt{3}\ cm$

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

$AB=2CA=16\sqrt{3}\ cm$

By the Pythagorean theorem,

$BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm$

3 0

2 years ago

The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has

Neko [114]

Given:

The dimensions:

Square pyramid

Square base: 2x2

1 out of 4 triangles: 1/2x2x5

4 triangles: 2x2x5

To find:

The SURFACE AREA of the square pyramid

Find answer:

Step 1

Find the area of the square base -

Square base:

SA = L x W

= 2 x 2

= 4

<em>The surface area of the square is 4 square inches</em>

<em></em>

Step 2

Find the area of the 4 Triangles:

We will use a different formula here, to find 1 triangle, we will have to do:

$SA = \frac{1}{2} *B*H$

To find 2 triangles, we will do:

$SA = B*H$

But to find 4 triangles in just 1 step, we will do:

$SA=2*B*H$

Let's do it!

$SA = 2*2*5\\=2*10\\=20$

<em>The surface area of the 4 triangles are 20 square inches</em>

<em></em>

Step 3

Add answers to get FINAL ANSWER

Easy!

20+4=24

<h2>Hence, the Surface Area of the Square Pyramid is 24 square inches</h2>

<em></em>

<em></em>

4 0

1 year ago

What's the additive identity of 9

Zigmanuir [339]

9? Thats what it is,

5 0

3 years ago

A. Sam purchased 3 games for $140 after a discount of 30%. What was the original price?

Semmy [17]

Answer:

a) $175 b) It will be $126

Step-by-step explanation:

Cost price of 3 games= $140

Let the original price of games= $ x

Discount is given= 30%

According to question

x $\frac{(100-20)}{100}$ = $140

x $\frac{80}{100}$ = $140

x ×0.8= $140

x= $ $\frac{$140}{0.8}$

x= $175

Hence, the original price of games $ 140

(b) If Sam had given a discount of 20%

Again a discount = 10%

The price of games=$ 140

Now, the selling price will be= 175 $\frac{(100-20)}{100}$ × $\frac{(100-10)}{100}$

Now, the selling price will be= $ 126

Hence, the price will be different.

7 0

3 years ago