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2 years ago

(3 + 6n+ 3n) – (3n + 3n3 – 2n")

Mathematics

1 answer:

Veseljchak [2.6K]2 years ago

7 0

Answer:

Step-by-step explanation:

6+3+3=15n

3+33-2=34

34-15=19n

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in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14

Colt1911 [192]

To show that the ratio $\frac{y}{x}$ is not constant for the function $y=a-14$ we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here $a$ represents $x$ .

To find the counter examples here, I will use the values $a=20$ and $a=28$ . For $a = 20$ , the equation tells us that the output is

$y=20-14=6$ . For this value of $a$ the point is point is $(20,6)$ . The ratio $\frac{y}{x} =\frac{6}{20}$ . For the $a=28$ , $y=28-14=14$ . For this value of $a$ the point is $(28,14)$ . The ratio $\frac{y}{x} =\frac{14}{28} =\frac{1}{2}$ . Clearly this ratio is not constant for all ordered pairs.

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2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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2 years ago

Need help if anything can show me how to do it in steps !

Elanso [62]

Answer:

x=59/5 or x=11.8 depends on which one you want to do both are true

Step-by-step explanation:

Start with what you are given

angle 4= 5x+6 and angle 3=65 because lines m and n are both parallel angle4=angle3 in other words 5x+6=65

what you want to do is get x by itself.

1. Subtract 6 from both sides

5x+6-6=65-6

5x=59

2. Divide both sides by 5

5x/5=59/5

x=59/5

3. Check to see if you can simplify the fraction and if you teacher wants it in decimals or exact fraction.

x=59/5 or x=11.8 they are the same just ones a decimal the other is left as a fraction

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2 years ago

What is the sum of X2-3x+7 and 3x2+5X-9

Pie

$x^2-3x+7+3x^2+5x-9=\ \ \ \ | combine\ like\ terms\\\\
4x^2+2x-2\\\\
Solution\ is\ 4x^2+2x-2.$

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2 years ago

Which of the following is equivalent to 5 · (7 · 4)? *

MariettaO [177]

B because you multiply 7 times 4 that’s 28 then times 5 that’s 140 so for b you do 5 times 7 that’s 35 then times 4 that’s 140 so b is the correct answer, hope it helps

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2 years ago