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iren2701 [21]
3 years ago
8

HELPP!!!!!!! Write in mx+b format.

Mathematics
1 answer:
Sloan [31]3 years ago
3 0

Answer:

y=3x+4

Step-by-step explanation:

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Which equation represents the line that passes through the point (1,5) with a slope of-2
svlad2 [7]

Answer:

The equation of the line would be y = -2x + 7

Step-by-step explanation:

In order to solve this, use the point and the slope in point-slope form. Then solve for y.

y - y1 = m(x - x1)

y - 5 = -2(x - 1)

y - 5 = -2x + 2

y = -2x + 7

3 0
3 years ago
Solve the given inequality and SHOW YOUR WORK<br> -2x + 3 &lt; 5
natita [175]

-2x<5-3

-2x<2

divide both sides by -2

x<-1

remember +/-=-

that's why it's a negative answer

4 0
3 years ago
Find (a) arc length and (b) Area of a sector.
barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

\textsf{Arc length}=r \theta

\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta

\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}

<u>Calculation</u>

Given:

  • \theta=\dfrac{5 \pi}{8}
  • r = 15 cm

\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}

5 0
2 years ago
Fiona finds 1 shell on her first day at the beach. every day that wek she finds twice as many shells as she did the day before.
attashe74 [19]
Ok, so on the first day she finds one, the second she finds two, the third four, the fourth eight, the fifth sixteen, the sixth thirty two, and the seventh sixty four. The answer is 64
6 0
3 years ago
Read 2 more answers
Select whether to use the Pythagorean Theorem or its converse in each situation.
alina1380 [7]
The side is 15ft long
3 0
3 years ago
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