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MrRa [10]
2 years ago
5

Help please thank u so much

Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
3 0

Answer:

Your answer is A

Step-by-step explanation:

Its just simple counting

kiruha [24]2 years ago
3 0
A) 83,711 because of the fact that it’s just the next integer
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Point K is rotated 90°. The coordinate of the pre-image point K was (2, –6) and its image K’ is at the coordinate (−6, −2). Find
aalyn [17]

Answer:

A clockwise rotation.

Step-by-step explanation:

The rule for 90 degree clockwise rotation is (x,y) turns into (y,-x) therefore if you use your numbers (2,-6) and then use the 90 degree clockwise rotation rule it becomes (-6,-2)

5 0
3 years ago
Algebra one help please?
IrinaVladis [17]

<u>During the first hour</u> . . .

5% of the 1,000 bacteria die.  At the end of the hour, 95% of them are left.

                                    95%  of  1,000  =  950

Then 100 are added :          950 + 100 = 1,050

<em>1,050</em> bacteria swimming around in the soup as the second hour begins.

<u>During the second hour</u> . . .

5% of the 1,050 bacteria die.  At the end of the hour, 95% of them are left.

                                          95%  of  1,050  =  997.5

Then 100 are added :             997.5 + 100 = 1,097.5 . . . . . <em>1,098</em> rounded

===================================

<u>Playing with this some more</u>:

If the same process continues, and the result at the end of each hour
is rounded to the nearest whole number, then the number of bacteria
steadily increases, but only for 88 hours.  At the end of the 88th hour,
there are 1991 of the little critters, and after that, the population stays
constant at  1991.  That's because the 5% loss during each hour after
that is  (5% of 1,991) = 99.55 , which rounds to 100, and those are
replaced by the 100 new ones.


3 0
4 years ago
Find the 50th term of this arithmetic sequence:<br><br> 6, 13, 20, 27, . . .
sladkih [1.3K]

Answer: 349

Step-by-step explanation:

Using the arithmetic sequence, it would add up to be 349

7 0
2 years ago
Find products of (SinA+CosA)* (SinA_ CosA)​
Advocard [28]

Answer:

(sin2A--cos2A)

hope this helps you

4 0
3 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
4 years ago
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