Pythagorean Therom
a^2 + b^2 = c^2
5^2 +b^2 = 7^2
25=b^2 = 49
49-25=b^2
49-25=14
b^2=24
b=sqrt24
sqrt24=4.89898
First, think of your places. You have the ones places, tens places, hundreds places, and so on.
The first number starting from the right is the ones, and as you keep going left, the value of each given digit becomes higher.
Since 5 is in the ones place, its value would be just 5. If it were in the tens place, it would be 50. If it were in the hundreds place, it would be 500, and so on.
Think of it this way;
Ones is just one. If a number is in the 'ones' place, its value would be a single digit. If it were in the tens place, its value would be two digits.
That's how it would be for each place going left.
Every number you move to the left, its value gains a one.
So here's an example:
5555
The value of 5 in the ones place "5555" is simply 5.
In the tens place, you end up adding one zero, so the value of the second five to the left would be, "50"
So with that said, the value of the digit 5 in the number 75 is <em>5.
</em>Haha, hope this cleared up any confusion, and have a <em>wonderful </em>day! :)<em>
</em>
Answer:
Check the explanation
Step-by-step explanation:
Let 
be the indicator random variable that takes the value 1 if the ith coin is the first coin in a sequence of 19 consecutive heads.
For any sequence of length 19, the starting coin can be from toss i ,
such that i is between 1 and n - 19+1
Thus the number of such sequences is
Kindly check the attached image below for the step by step explanation to the question above.
In order to solve this, you have to plug in all of the costs of the gifts and add them, which in all equals $36. since jim only has 1/4 of the money he needs to buy the gifts, you need to divide 36 by 4. this gives you 9, so now you know he has 9 dollars.
and to find out how much more money he needs, you can subtract 9 from 36 which represents a fourth of the required money. the answer is 27, that's how much jim needs in order to buy his gifts.
