Human trafficking in South Africa is still a critical problem that must be tackled with laws protecting citizens and actively combating this situation.
<h3 /><h3>How to abolish human trafficking?</h3>
It is essential that there are consistent government measures to control and combat this situation, to extinguish this situation that violates the human rights to life, security and liberty.
Therefore, every human being has the right to the protection of their essential rights, and it is up to the government of a country to implement strict rules and laws to combat human trafficking and promote better life opportunities.
Find out more about human trafficking here:
brainly.com/question/1163922
Answer:
Drinking excessive amount of water can cause low sodium by over whelming the kidney's ability to excrate water. Because you loose sodium through sweat, drinking too much water duting marathons and triathlons, can also dilute the sodium content of your blood...
The indefinite integral expressed as an infinite series is;
![= (\Sigma^{\infty} _{n = 0} (-1)^{n} \frac{1 }{2n + 1} * \frac{(x)^{4n + 3}}{4n + 3}) + C](https://tex.z-dn.net/?f=%3D%20%20%28%5CSigma%5E%7B%5Cinfty%7D%20_%7Bn%20%3D%200%7D%20%28-1%29%5E%7Bn%7D%20%5Cfrac%7B1%20%7D%7B2n%20%2B%201%7D%20%2A%20%5Cfrac%7B%28x%29%5E%7B4n%20%2B%203%7D%7D%7B4n%20%2B%203%7D%29%20%2B%20C)
<h3>How to find indefinite integral?</h3>
We will first have to look for the Maclaurin series of arctan(x).
We'll recall that from online tables of integral, this Maclaurin series of arctan(x) will have the general formula;
![arctan(x) = \Sigma^{\infty} _{n = 0} (-1)^{n} \frac{x^{2n + 1} }{2n + 1}](https://tex.z-dn.net/?f=arctan%28x%29%20%3D%20%20%5CSigma%5E%7B%5Cinfty%7D%20_%7Bn%20%3D%200%7D%20%28-1%29%5E%7Bn%7D%20%5Cfrac%7Bx%5E%7B2n%20%2B%201%7D%20%7D%7B2n%20%2B%201%7D)
When we apply that general Maclaurin series of arctan(x) to our question of arctan(x²), we have the expression as;
![arctan(x^{2} ) = \Sigma^{\infty} _{n = 0} (-1)^{n} \frac{(x^2)^{2n + 1} }{2n + 1}](https://tex.z-dn.net/?f=arctan%28x%5E%7B2%7D%20%29%20%3D%20%20%5CSigma%5E%7B%5Cinfty%7D%20_%7Bn%20%3D%200%7D%20%28-1%29%5E%7Bn%7D%20%5Cfrac%7B%28x%5E2%29%5E%7B2n%20%2B%201%7D%20%7D%7B2n%20%2B%201%7D)
⇒ ![= \Sigma^{\infty} _{n = 0} (-1)^{n} \frac{(x)^{4n + 2} }{2n + 1}](https://tex.z-dn.net/?f=%3D%20%20%5CSigma%5E%7B%5Cinfty%7D%20_%7Bn%20%3D%200%7D%20%28-1%29%5E%7Bn%7D%20%5Cfrac%7B%28x%29%5E%7B4n%20%2B%202%7D%20%7D%7B2n%20%2B%201%7D)
We now integrate the expression that we got above in the following manner to get;
![\int\limitsarctan(x^{2} ) = \int\Sigma^{\infty} _{n = 0} (-1)^{n} \frac{(x)^{4n + 2} }{2n + 1} dx](https://tex.z-dn.net/?f=%5Cint%5Climitsarctan%28x%5E%7B2%7D%20%29%20%3D%20%20%5Cint%5CSigma%5E%7B%5Cinfty%7D%20_%7Bn%20%3D%200%7D%20%28-1%29%5E%7Bn%7D%20%5Cfrac%7B%28x%29%5E%7B4n%20%2B%202%7D%20%7D%7B2n%20%2B%201%7D%20dx)
⇒ ![= (\Sigma^{\infty} _{n = 0} (-1)^{n} \frac{1 }{2n + 1} * \frac{(x)^{4n + 3}}{4n + 3}) + C](https://tex.z-dn.net/?f=%3D%20%20%28%5CSigma%5E%7B%5Cinfty%7D%20_%7Bn%20%3D%200%7D%20%28-1%29%5E%7Bn%7D%20%5Cfrac%7B1%20%7D%7B2n%20%2B%201%7D%20%2A%20%5Cfrac%7B%28x%29%5E%7B4n%20%2B%203%7D%7D%7B4n%20%2B%203%7D%29%20%2B%20C)
Thus, that expression gives us the indefinite integral of arctan(x²) as an infinite series.
Read more about the indefinite integral at; brainly.com/question/12231722
This is because I’d deep ocean,tsunami waves may appear only a foot or so high.But as they approach the shoreline and enter shallower water they slow down and begin to grow in energy and height.Since the tops of the waves move faster than the bottoms so it causes them to rise faster.So...if a tsunami is in deep waters it does not really hit the shore and splash around to hurt anyone or anything or any people.It is fine because it’s in the middle of the ocean and not on the shoreline.I hoped I helped even a little bit :3
A and B
The other answers do not correctly use a semi-colon because the semicolon acts as a period that connects two closely related clauses.