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suter [353]
3 years ago
14

Additive inverse of -2/5​

Mathematics
1 answer:
Inessa [10]3 years ago
4 0

Hello! The additive inverse of -2/5 is 2/5.

if you add -2/5+2/5, you will get 0, so these two numbers are opposites and additive inverses.

Hope this helps you!

~Just a joyful teen

SilentNature\\(GraceRosalia)

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Reil [10]

4^10 and x^4 are the right answers

3 0
3 years ago
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HELP FAST IT'S TIMED
anygoal [31]

Answer:

d = 1/2

Step-by-step explanation:

5/6 = 1/3 + d

~Find common denominators

5/6 = 2/6 + d

~Subtract 2/6 to both sides

3/6 = d

~Simplify

1/2 = d

Best of Luck!

4 0
3 years ago
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The expression below is the factorization of what trinomial-1(x+5)(x+6)
Nadya [2.5K]

Answer:

-x^2 - 11x -30

Step-by-step explanation:

Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.

ie: x(x) and x(6)

ie: x^2 + 6x

Then do the 5 times the things in the second parenthesis.

ie: 5(x) and 5(6)

ie: 5x + 30

Then add what you got from multiplying the first value to what you got from multiplying the second.

ie: x^2 + 11x + 30

This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.

ie: -x^2 - 11x -30

4 0
3 years ago
❊ Simplify :
Nataliya [291]
<h3>Need to Do :- </h3>
  • To simplify the given expression .

\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }

\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

5 0
3 years ago
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how could you rephrase the inequality, x &gt; 6? A. x less than 6 b. x is greater than 6 c. x is greater than or equal to 6 D. x
Sliva [168]

Answer:

the answer is A

Step-by-step explanation:

5 0
3 years ago
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