Answer:
b
Step-by-step explanation:
ITS B NOT C ITS B ITS B ITS B.
Hello!
We can begin by solving for c₃ given the equations:
c₃ = 3c₂ + 2c₁ - 2
c₃ = 3(2) + 2(4) - 2
Simplify:
c₃ = 6 + 8 - 2 = 12
We can now find the subsequent terms:
c₄ = 3(12) + 2(2) - 2 = 38
c₅ = 3(38) + 2(12) - 2 = 136
- - = + 9-(-4)= 9+4 so minus minus becomes plus. and 13 is the answer.
Answer:
(53.812 ; 58.188) ; 156
Step-by-step explanation:
Given that :
Sample size (n) = 51
Mean (m) = 56
Standard deviation (σ) = 9.5
α = 90%
Using the relation :
Confidence interval = mean ± Error
Error = Zcritical * (standard deviation / sqrt (n))
Zcritical at 90% = 1.645
Error = 1.645 * (9.5 / sqrt(51))
Error = 1.645 * 1.3302660
Error = 2.1882877
Hence,
Confidence interval :
Lower boundary = 56 - 2.1882877 = 53.8117123
Upper boundary = 56 + 2.1882877 = 58.1882877
Confidence interval = (53.812 ; 58.188)
2.)
Margin of Error (ME) = 1.25
α = 90%
Sample size = ((Zcritical * σ) / ME)^2
Zcritical at 90% = 1.645
Sample size = ((1.645 * 9.5) / 1.25)^2
Sample size = (15.6275 / 1.25)^2
Sample size = 12.502^2 = 156.3000
Sample size = 156
1/2 + 2/5 = 5/10 + 4/10 = 9/10
