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Olegator [25]
3 years ago
11

What is 5/4÷1/10? because i don't know what it is

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0

Answer:

25/2

Step-by-step explanation:

Ganezh [65]3 years ago
4 0

\bold{Hello~!}

What is ^5^/^4 ÷ ^1^/^1^0~^?

<h2>✧ ANSWER : </h2><h2 /><h2>0.125</h2><h2 /><h2>☆ EXPLANATION : </h2><h2 />

^5^/^4 ÷ ^1^/^1^0~^?

\sf{Divide~the~numbers:}~5 ÷ \sf{4 = 1.25

\sf{= 1.25} ÷ \sf{~1} ÷ \sf{10}

\sf{Divide~the~numbers:}~1.25 ÷ \sf{~1} \sf{ = 1.25}

\sf{= 1.25} ÷ \sf{10}

\sf{Divide~the~numbers:~1.25 ÷ \sf{10} \sf{= 0.125}

\sf{ 0.125}

Hope It Helps!

#LearnWithBrainly

\underline{Answer~:}

\sf{Miwsow}

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3 years ago
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Write a two step equation involving division and addition that has a solution of x = 25
White raven [17]
5x+10=25
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Solve 3.4 [ 6 ( 4) +6^2]<br><br> Please show your work! &lt;3
VARVARA [1.3K]

Answer:

204

Step-by-step explanation:

3.4[6(4)+6^2]=

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7 0
3 years ago
Which point is on the graph of f(x)=5^x
borishaifa [10]

Answer:

y=0

Step-by-step explanation:

x           y

-2         0.04

-1           0.2

0          1

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8 0
3 years ago
One freezer costs $623.95 and uses 90 kilowatt hours (kwh) of electricity each month. A second freezer costs $500 and uses 100 k
lutik1710 [3]

The minimum electric rate in cents per kwh for which the 12-year total cost will be less for the first freezer is 8.61 cents

<h3>How to calculate the rate?</h3>

Let x =  minimum electric rate (Cents/kWh)

Total months in 12 years is 12*12 = 144 m

1st freezer

Total cost over 12 years is

623.95 (cost) + (90 kWh/m)*(144 m)(x/100 $/kWh)

= 623.95 + 129.6x

2nd freezer

Total cost over 12 years is

500 + 100*144*(x/100)

= 500 + 144x

For the 1st freezer to cost less over 12 years,

623.95 + 129.6x < 500 + 144x

123.95 < 14.4x

8.61 < x

The minimum rate is 8.61 cents per kWh

Learn more about rate on:

brainly.com/question/25537936

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8 0
2 years ago
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