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frez [133]
3 years ago
11

Which table has a constant of proportionality between y and x of 3/4?

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0

x of 3/4 = x10 abd y 19/2 or 11

mina [271]3 years ago
7 0
B because 3/3/4 is equal to 4/4/3 and 5/5/3
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Use Newton’s Method to find the solution to the equation
Scorpion4ik [409]

f(x) =  - x {}^{2}  + 18 \\ f'(x) = - 2x

x_{n + 1} = x_{n} -  \frac{f(x_{n})}{f'(x_{n})}

x_{2} = 3  -  \frac{f(3)}{f'(3)}  = 4.5

x _{3}= 4.5 -  \frac{f(4.5)}{f'(4.5)}  = 4.25

x_{4} = 4.25 -  \frac{f(4.25)}{f'(4.25)}  ≈4.242647

x_{5} = 4.242647 -  \frac{f(4.242647)}{f'(4.242647)}  ≈4.242640 \\

6 0
1 year ago
Football practice starts at 5:45 P.M. and lasts for 80 minutes. What time does football practice end?
bija089 [108]

Answer:

7:05

Step-by-step explanation:

We start with 5:45.

Add 60 minutes / an hour to get 6:45.

We have 20 minutes left to add.

Add 15 minutes to get 7:00.

Add 5 more to get 7:05.

4 0
3 years ago
Read 2 more answers
Express the area of the entire rectangle
Tema [17]

Answer:

x^2+11x+30

Step-by-step explanation:

(x+6)(x+5)

x^2+5x+6x+30

x^2+11x+30

3 0
3 years ago
Find the rate of change of the area of a square with respect to the length z , the diagonal of the square. what is the rate when
Reil [10]
The diagonal of a square is equal to the side x times square root of 2, xSqrt(2)
z = xSqrt(2), its rate of change is just Sqrt(2)
4 0
3 years ago
Need help with inscribed angles If M
Cloud [144]

Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and m\angle BCD=30^\circ.

To find:

The m\angle AOB.

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

\angle OBA\cong \angle BCD        [Alternate interior angles]

m\angle OBA=m\angle BCD

m\angle OBA=30^\circ

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

The base angles of an isosceles triangle are congruent. So,

\angle OAB\cong \angle OBA      [Base angles of an isosceles triangle]

m\angle OAB=m\angle OBA

m\angle OAB=30^\circ

Using the angle sum property in triangle AOB, we get

m\angle OAB+m\angle OBA+m\angle AOB=180^\circ

30^\circ+30^\circ+m\angle AOB=180^\circ

60^\circ+m\angle AOB=180^\circ

m\angle AOB=180^\circ-60^\circ

m\angle AOB=120^\circ

Hence, the measure of angle AOB is 120 degrees.

4 0
3 years ago
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