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olga55 [171]
2 years ago
10

t="\sqrt{72x^{7} q^{8} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Jet001 [13]2 years ago
8 0
Attachment picture is the solution. Please mark me brain if you think it help. Thank you!

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A small bar of gold measures 20 mm by 150 mm by 2 mm. One cubic milimeter of gold weighs about 0.0005 ounces. Find the volume in
Kay [80]

Answer:

= 3oz

Step-by-step explanation:

v = 20mm ×150mm ×2mm = 6000 mm^3

so, the weight is

6000 mm^3 × 0 .0005oz/1mm^3 = 3oz

6 0
2 years ago
At 7:00 am, the temperature was -4℉. At 9:00 am, it was 8° warmer. What was the temperature at 9:00 am? *
Nana76 [90]

<em>4℉.</em>

What we know about Degrees is that there is a<em> </em><u><em>Positive</em></u> type and a <u><em>negative</em></u> type.

(i.e: 30℉ is <u><em>positive</em></u> and -30℉ is <u><em>negative</em></u>.)

If the temperature was -4℉ at 7AM, then it is negative. If it goes up by an amount that is more than 4 then that negative will go up to a positive temperature. In this case: At 9AM it was 8° <u><em>warmer</em></u>.

<u><em>Warmer</em></u><em> is a </em><u><em>keyword</em></u><u>.</u> If it is warmer by an amount, Negative temperatures <u><em>will go up to a positive</em></u> and positive temperature <u><em>will just go up</em></u>. If it gets cooler, negative temperatures <u><em>will go down further</em></u> and positive temperatures <u><em>will go down to a negative</em></u>.

So lets work out this problem with our newfound knowledge.

-4° F at 7AM

8°  warmer at 9AM

-4 + 8 = 4.

<em>The temperature was 4°  at 9AM.</em>

-Snooky

8 0
2 years ago
Draw a rectangular fraction model to explain your thinking. Then, write a multiplication sentence. What is 4/9 x 3/8 ?
ELEN [110]

Answer:

The multiplication sentence is 4/9*3/8=1/6

then for the rectangular fraction model draw two rectangles and in the first one draw 9 boxes and shade in 4. Then, in the second one draw 8 boxes and shade 3.

Step-by-step explanation:

This is an example:

8 0
3 years ago
What is the distance between -7.5 and -15.3 on a number line
timama [110]
Okay. To find the distance apart from each other, subtract 15.3 and 7.5. When you do that, you should get 7.8. -7.5 and -15.3 are 7.8 units away on a number line.
8 0
2 years ago
Write an expression in terms of x that represents the distance between (2,10) and (x,10) for x&gt;2.
ehidna [41]

Answer:

Step-by-step explanation:

d=\sqrt{(x-2)^2+(10-10)^2} =\sqrt{(x-2)^2}=x-2

7 0
3 years ago
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