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3 years ago

What is the value for X?

Mathematics

1 answer:

Marta_Voda [28]3 years ago

4 0

X=21 and the mesure of one would be 120 to check if its correct multiply 5 by 21 then add it to 15 and that would be the answer for what 1 is you can also check of its 21 by multiplying 3 by 21 and subtracting 3 then adding both to get 180 which is the normal measurements of the line. hope this helps somehow

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Thirty-two million,five thousand,eight

Over [174]

In standard form, 32,005,008

6 0

4 years ago

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What is the distance between the points (2,6) and (5,8)? Round to the

lidiya [134]

The distance between given points is 3.6 units.

Step-by-step explanation:

Given points are;

(2,6) and (5,8)

Here;

$x_1=2\\y_1=6\\x_2=5\\y_2=8$

Distance between two points is calculated by;

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\Distance = \sqrt{(5-2)^2+(8-6)^2}\\\\Distance = \sqrt{(3)^2+(2)^2}\\\\Distance = \sqrt{(9+4)}\\\\Distance = \sqrt{13}\\\\Distance=3.6\ units$

The distance between given points is 3.6 units.

Keywords: distance, points

Learn more about distance at:

#LearnwithBrainly

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3 years ago

It is predicted that in t years, the population of a country will be P (t) = 50e ^ (0.02t) million inhabitants. A) What will be

lakkis [162]

$\begin{gathered} \text{Given:} \\ P(t)=50e^{0.02t} \end{gathered}$

A) What will be the rate of change of the population in 10 years.

$\begin{gathered} \text{Get the derivative of the }P(t)\text{ with respect to }t \\ \frac{dP}{dt}(50e^{0.02t})=50(0.02)e^{0.02t} \\ \frac{dP}{dt}(50e^{0.02t})=e^{0.02t} \end{gathered}$

Substitute t = 10, to the derivative of P(t)

$\begin{gathered} P^{\prime}(t)=e^{0.02t} \\ P^{\prime}(10)=e^{0.02(10)} \\ P^{\prime}(10)=e^{0.2} \\ P^{\prime}(10)=e^{0.2} \\ P^{\prime}(10)=1.02020134 \\ \\ \text{Round off to two decimal place} \\ P^{\prime}(10)=1.02 \end{gathered}$

Therefore, the rate of change of the population in 10 years is 1.02 million.

B) What will be the relative rate of the population in t years? Is this rate constant?

$\begin{gathered} \text{The relative rate of the population in t years is the first derivative of }P(t) \\ P^{\prime}(t)=e^{0.02t} \end{gathered}$

The rate is not constant, as it depends on how much time t has passed.

5 0

1 year ago

Is this triangle acute, right, or obtuse?

BlackZzzverrR [31]

Answer:

acute

hope this helps

have a good day :)

Step-by-step explanation:

7 0

3 years ago

How do you solve 6-9(4p-3)= 2(6p+7)+3

Alika [10]

Answer:

p= 1/3

=0.333

Step-by-step explanation:

Simplifying

6 + -9(4p + -3) = 2(6p + 7) + 3

Reorder the terms:

6 + -9(-3 + 4p) = 2(6p + 7) + 3

6 + (-3 * -9 + 4p * -9) = 2(6p + 7) + 3

6 + (27 + -36p) = 2(6p + 7) + 3

Combine like terms: 6 + 27 = 33

33 + -36p = 2(6p + 7) + 3

Reorder the terms:

33 + -36p = 2(7 + 6p) + 3

33 + -36p = (7 * 2 + 6p * 2) + 3

33 + -36p = (14 + 12p) + 3

Reorder the terms:

33 + -36p = 14 + 3 + 12p

Combine like terms: 14 + 3 = 17

33 + -36p = 17 + 12p

Solving

33 + -36p = 17 + 12p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-12p' to each side of the equation.

33 + -36p + -12p = 17 + 12p + -12p

Combine like terms: -36p + -12p = -48p

33 + -48p = 17 + 12p + -12p

Combine like terms: 12p + -12p = 0

33 + -48p = 17 + 0

33 + -48p = 17

Add '-33' to each side of the equation.

33 + -33 + -48p = 17 + -33

Combine like terms: 33 + -33 = 0

0 + -48p = 17 + -33

-48p = 17 + -33

Combine like terms: 17 + -33 = -16

-48p = -16

Divide each side by '-48'.

p = 0.3333333333

Simplifying

p = 0.3333333333

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3 years ago

Read 2 more answers