At x = 0, y-coordinate is at -4 so that means f(0) = -4
Now for f(x) = 4, we need to find any x-coordinates such that y-coordinates is 4.
There are two possible answer: x = -8 and x = 8
So x = -8, 8
Hope this helps.
I=prt
i=2000 X .04 X 7
i = 560
So you earned 560 after 7 years, plus your 2000 you started with
You can get C
Answer:
Step-by-step explanation:
8 times 6 = 48 (base times high = a rectangle). (A triangle takes half the space)
F. (6*8)/2 =24 square units
B. (2 * 3/2) / 2 = 3/2 = 1.5 square units
G. (4*3)/2 = 6 square units
H. (8/3 *2)/2 = 8/3 = 2.67 square units
The polynomial cannot be factored in because it exists prime. Since 112 exists not a perfect square number so we cannot estimate the factors of the given equation.
<h3>What is a quadratic equation?</h3>
In a quadratic equation ax² + bx + c = 0
when (b² - 4ac) exists a perfect square only then we can factorize the equation.
In the given equation x² - 8x - 12 we have to determine the value of
b² - 4ac
From the equation, we get b = -8 and c = -12
b²- 4ac = (-8)² - 4(1)(-12)
= 64 + 48 = 112
Since 112 exists not a perfect square number so we can not estimate the factors of the given equation.
To learn more about quadratic equation refer to:
brainly.com/question/1214333
#SPJ4
