<u>Threat </u>is some danger that can exploit a vulnerability.
<h3>What is Threat?</h3>
Threat is seen as Anything that can be able to take advantage of a vulnerability, intentionally as well as accidentally, and take or damage, the asset of a person.
Note that a threat is that which a person or firm is protect against and Vulnerability is seen as Weaknesses.
Therefore, <u>Threat </u>is some danger that can exploit a vulnerability.
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Answer:
by it scan properly like you use Camara
when we use camara and it have record time like that it also have that type of scan data so that the computer use
sorry I don't no other thing and I an sorry for the very short answer
Discuss why different user interfaces require the use of different types of input device. Page 15. What is Secondary Storage? List 3 Storage Mediums: What is ...
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1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
The right side to a semi tractor trailer is their huge blind side, meaning the driver can't see you, and may merge lanes with you, thus crashing into you.
