I could be wrong, but it seems that there are only 2 possible squares in this grid.
•One square has a side length of 2, meaning that the area is 2x2 which is 4 units squared (can be written as 4 units^2)
•The other square has side lengths of 1. 1x1=1 unit^2.
We know that the domain is actually the number of rolls
that she gets because it is the input variable in the equation f (r) = 40 r + 26. The number of rolls that
she can get can never be a negative number nor a zero nor a decimal number.
However she can only get up to 10 rolls. Therefore the answer is:
all integers from 1 to 10, inclusive
the cheap answer is simply
(x-5)(x²+4x-2)
we can simply multiply the terms on one by the terms of the other and then add like-terms and simplify.
![\bf (x-5)(x^2+4x-2)\implies \begin{array}{cllll} x^2+4x-2\\ \times x\\ \cline{1-1}\\ x^3+4x^2-2x \end{array}+ \begin{array}{cllll} x^2+4x-2\\ \times -5\\ \cline{1-1}\\ -5x^2-20x+10 \end{array} \\\\\\ x^3+4x^2-2x-5x^2-20x+10\implies x^3+4x^2-5x^2-2x-20x+10 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-22x+10~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%28x-5%29%28x%5E2%2B4x-2%29%5Cimplies%20%5Cbegin%7Barray%7D%7Bcllll%7D%20x%5E2%2B4x-2%5C%5C%20%5Ctimes%20x%5C%5C%20%5Ccline%7B1-1%7D%5C%5C%20x%5E3%2B4x%5E2-2x%20%5Cend%7Barray%7D%2B%20%5Cbegin%7Barray%7D%7Bcllll%7D%20x%5E2%2B4x-2%5C%5C%20%5Ctimes%20-5%5C%5C%20%5Ccline%7B1-1%7D%5C%5C%20-5x%5E2-20x%2B10%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5C%5C%20x%5E3%2B4x%5E2-2x-5x%5E2-20x%2B10%5Cimplies%20x%5E3%2B4x%5E2-5x%5E2-2x-20x%2B10%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20x%5E3-x%5E2-22x%2B10~%5Chfill)
The inverse of a function will also be a function if it is a One-to-One function. This means, if each y value is paired with exactly one x value then the inverse of a function will also be a function.
Option C gives us such a function, all x values are different and all y values are different. So inverse of function given in option C will result in a relation which will also be a function.
In all other options, y values are being repeated, which means they are not one to one functions.
So, the answer to this question is option C
C. 3x-2 1. you split the second terms into two terrms.
2. factor out common terms in the first two terms, then in the last two terms
3. factor out the common term 3x-2
cancel out x-5
and your left with 3x-2
