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padilas [110]
3 years ago
14

What is the slope of a line perpendicular to the line whose equation is x +y= 2.

Mathematics
1 answer:
pogonyaev3 years ago
8 0

Answer:

x + y =2

-x         -x

y = -1x + 2

Perpendicular is y= 1x + 2

Step-by-step explanation:

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A normal distribution in which approximately 68% of the data values fall within one standard deviation of the mean behaves accor
Komok [63]
That's the empirical rule.  Very useful!

3 0
4 years ago
If 4 people ate at a restaurant. If each person paid an equal amount who would save the most money
Crank

Answer:

You will want to add up the total for all four guests (The one after you added the tip) and then since you want to split it evenly, you can multiply it by 1/4.

3 0
3 years ago
Read 2 more answers
Please helpp me thank you 20 pts
pogonyaev
I'm pretty sure it is C

5 0
4 years ago
HELP!!
Lesechka [4]

Answer: Choice C

x < -2 \text{ or } x \ge 4

==========================================

Reason:

The portion on the left represents x < -2 because of the open circle at -2 and shading pointing to the left. This represents all numbers smaller than -2.

The portion on the right represents all values that are 4 or larger; hence x \ge 4. Note the use of a closed circle at 4 to include this value.

We connect those two inequalities with the keyword "or" because x can only pick one of those options, but not both at the same time.

4 0
2 years ago
Pls answer correct<br> for class 9 only
Len [333]

Answer:

hope it helps

Step-by-step explanation::

a) Consider a body having initial velocity 'u'. Suppose it is subjected to a uniform acceleration 'a' so that after time 't' its final velocity becomes 'v'. Now, from the definition of acceleration we know that:  

Acceleration =  Time taken  Change in velocity  or Acceleration =  time taken

                Final velocity- Initial velocity    

So, a=  t v−u

​ at=v−u  and, v=u + at  

where v= final velocity of the body

u= initial velocity of the body

a= acceleration

and t= time taken  

(b) Initial velocity, u=54km/h=15m/s

Final velocity, v=0m/s

Time, t=8s

Acceleration, a=?

a=  t v−u

​  =  8 0−15

​  =  8 −15 ​  m/s  2

=−1.875m/s  2

4 0
3 years ago
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