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2 years ago

PLZZZ HELPPP

Mathematics

2 answers:

Hatshy [7]2 years ago

5 0

The line intersects the y-axis at the point (0,3). Therefor the answer is A.

natali 33 [55]2 years ago

4 0

Answer:

I think its answer A I think so

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A girl ran from her home to a store at the rate of 6 mph, and she walked back home at the rate of 4 mph. if it took 15 minutes f

viva [34]

Home is 0.6 miles away from the store

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:-

Total time taken by girl to complete the trip = 15 minutes = $\frac{1}{4}$ hours

Speed while riding going = 6 miles per hour

Speed while coming back = 4 miles per hour

Total time taken by girl =

Time taken while going + Time taken while coming back - (1)

Let x be distance from home to store

$\frac{x}{6}$ = Time taken while going

$\frac{x}{4}$ = Time taken while coming back

Substituting in (1) we get

$\frac{1}{4} = \frac{x}{6} + \frac{x}{4}$

$\frac{1}{4} = \frac{2x + 3x}{12}$

$\frac{1}{4} = \frac{5x}{12}$

$x= \frac{12}{20}$

x = 0.6 miles

Thus home is 0.6 miles away from the store

Learn more about time related here :

brainly.com/question/12759408

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6 0

1 year ago

If the ratio of y to x is equal to 3 and the sum of y and x is 80, what is value of y

Rus_ich [418]

Answer:

y = 60

Step-by-step explanation:

<h3>Step 1: Make sense of the given</h3>

"The ratio of y to x is 3"

This means that, $y\div x=3$

"The sum of y and x is 80"

This means, $x+y=80$

<h3>Step 2: Make use of the facts</h3>

If $y\div x=3$ , then $y = (3*x)$ .

We can plug this into the other equation by substitution:

$x + (3 * x)=80$

This simplifies to:

$4x = 80$

Which we can solve out and get:
$x=20$ .

We solved for x, but we need the value of y.

So, we go back to the equation we first derived: " $y = (3*x)$ ".

And now we substitute the value of x, into this.

$y = (3 * (20))$

By solving this out, we get:
$y=60$

So, the value of y is 60.

3 0

1 year ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$