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Alexeev081 [22]
3 years ago
6

BASEBALL John had 30 baseball cards.

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0

Answer:

John has 9 baseball cards left.

Step-by-step explanation:

First, you have to find how many baseball cards John has in the begining before he starts giving them away. In the problem, it states that John had 30 baseball cards.

Next, you have to find how how many he gave away. In the problem, it states that he gave 14 to Mike and 7 to Jeff. Instead of subtracting the numbers one by one, we'll make it easier. Add 14 to 7 and you'll get 21.

Then, you subtract 21 from 30, and you'll get 9.

John has 9 basball cards left.

P.S. If you want the equation, the equation is 30-(14+7)=x or 30-21=x

Degger [83]3 years ago
5 0

Answer:

john has 9 baseball cards left

Step-by-step explanation:

30 - 14 - 7 = 9

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Train travels at 3 hours if it's speed is 65 miles per hour. It takes the train 2.5 hours if it's speed is 78 per hour . Identif
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Step-by-step explanation:

Let the original speed of the train be x km/h.

Time taken to cover a distance of 360 km =  360/x hours.

New speed of the train = (x+5) km/h.

Time taken to cover a distance of 360 km at new speed = 360/x+5 hours.

Since, the train takes 1 hour less time,

∴360/x - 360/ x+5 = 1

⇒360 (5) = x² + 5x

⇒1800 = x² + 5x

⇒x² + 5x - 1800 = 0

⇒x² + 45x - 40x - 1800 = 0

⇒x (x+45) - 40( x +45) = 0

⇒(x+45) (x-40) = 0

⇒x = (-45), 40

But since speed cannot be in negative.

∴x = 40 km/hr.

Hence, the original speed of the train is 40 km/h.

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3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST PLEASE ANSWER If a circle is dilated by 5/3 and the area of the larger circle is 100pi square cm, then what
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Answer:

We have a small circle, that is dilated by a factor of 5/3 creating a larger circle.

If the smaller circle has a diameter D, then after the dilation, the larger circle will have a diameter equal to: (5/3)*D

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A = 100*pi cm^2.

And the area of a circle of diameter d, is:

a = pi*(d/2)^2

knowing that the diameter of the large circle is (5/3)*D, we can find the value of D.

A = pi*( (5/3)*D/2)^2 = 100*pi cm^2

let's solve this for D:

pi*( (5/3)*D/2)^2 = 100*pi cm^2

( (5/3)*D/2)^2 = 100 cm^2

( (5/3)*D/2) = √(100 cm^2) = 10cm

D/2 = (3/5)*10cm

D = 2*(3/5)*10cm = 12cm.

Then the area of the smaller circle will be:

a = pi*(D/2)^2 = pi*(12cm/2)^2 = pi*(6cm)^2 = pi*36 cm^2

and pi = 3.14

a = pi*36 cm^2 = 3.14*36cm^2 = 113.04 cm^2

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3 years ago
You ask 125 randomly chosen students to name their favorite food. There are 1500 students in the school. Predict the number of s
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The national average for the math portion of the College Board’s Scholastic Aptitude Test
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Answer:

a) 0.1587

b) 0.023

c) 0.341

d) 0.818

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 515

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

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= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%

b) b) P(score greater than 715)

P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)

Calculating the value from the standard normal table we have,

1 - 0.977 = 0.023 = 2.3\%\\P( x > 715) = 2.3\%

c) P(score between 415 and 515)

P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%

P(415 \leq x \leq 515) = 34.1\%

d) P(score between 315 and 615)

P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%

P(315 \leq x \leq 615) = 81.8\%

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Answer:

×1 = 3 : 8.

×2 = 6 : 16

×3 = 9 : 24

×4 = 12 : 32

Step-by-step explanation:

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