Earth diameter = 12,750 km
Earth radius = 6,375 km
Sphere Surface Area = <span> 4 • <span>π <span>• r²
</span></span></span>Sphere Surface Area = 4 * 3.141<span>59 * 6375^2
</span>Sphere Surface Area = 4 * 3.14159 *
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40,640,625
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</span>
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Earth's Entire </span></span></span><span>Surface Area = 510,704,724 square kilometers
Surface NOT covered by water = </span><span>510,704,724 * .3
</span>Surface NOT covered by water =
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153,211,417</span></span></span><span> square kilometers</span>
5/3 would be your best bet
Since (f/g)(x) = f(x)/g(x) for x to be in the domain of (f/g)(x) it must be in the domain of f and in the domain of g. You also need to insure that g(x) is not zero since f(x) is divided by g(x). Thus there are 3 conditions. x must be in the domain of f: f(x) = 3x -5 and all real numbers x are in the domain of x.
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find ( f o f )(x).
( f o f )(x) = f ( f (x))
= f (2x + 3)
= 2( ) + 3 ... setting up to insert the input
= 2(2x + 3) + 3
= 4x + 6 + 3
= 4x + 9
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x).
(g o g)(x) = g(g(x))
= –( )2 + 5 ... setting up to insert the input
= –(–x2 + 5)2 + 5
= –(x4 – 10x2 + 25) + 5
= –x4 + 10x2 – 25 + 5
= –x4 + 10x2 – 20
Answer:
4
Step-by-step explanation:
Hello!
To calculate how much 3 cakes would cost, we must first find the cost of each individual cake.
To do this, we must divide the cost of 8 cakes by 8 cakes.
4.00 ÷ 8 = 0.5
This means that each individual cake costs $0.50. Multiply this by 3 to find the cost of 3 cakes.
0.50 × 3 = 1.50
Therefore, 3 cakes would cost $1.50.