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emmasim [6.3K]
3 years ago
10

WILL MARK BRAINLIEST IF CORRECT!!!

Mathematics
2 answers:
blondinia [14]3 years ago
7 0

Answer:

False

Explanation: Not all Binomials that have a perfect square terms are factorable, as an example a binomial, x^2+9=x^2+3^2, has perfect square BUT aren’t factorable, it would only work if instead of x^2+9 it was x^2-9

natta225 [31]3 years ago
6 0

Answer:

false

Step-by-step explanation:

(8/4)/2 = 1

8/(4/2) = 4

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PLEASE HELP RATIOS TABLES DUE TOMARROW!!!!!!
Rasek [7]

Since the ratio is as simple as 1:2, just double each Euro value.

1:2, 2:4, 5:10, 10:20.


8 0
3 years ago
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Pls help find the amount at the end of 6 hours
marshall27 [118]

Answer:

A. 7,348

Step-by-step explanation:

P = le^kt

intitial population = 500

time = 4 hrs

end population = 3,000

So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.

A = Pe^rt

3,000 = 500e^r4

now we can solve for r

divide both sides by 500

6 = e^r4

now because the variable is in the exponent, we have to use a log

log_{e}(6) = 4r

ln(6) = 4r

we can plug the log into a calculator to get

1.79 = 4r

divide both sides by 4

r = .448

now lets plug it back in

A = 500e^(.448)(6 hrs)

A = 7351.12

This is closest to answer A. 7,348

4 0
3 years ago
1/2 times what =5<br><br><br> I need help pls its due tomorrow. :(
Mashcka [7]

Answer:

10

Step-by-step explanation:

half of 10 is 5

8 0
2 years ago
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Find rate of change help show work.
sukhopar [10]

Answer:

rise/run = 2/-4 or it is rise/run = -2/4

3 0
2 years ago
Which of the following points lie in the solution set to the following system of inequalities? y &gt; −3x + 3 y &gt; x + 2
OverLord2011 [107]

Answer:

y> -3x

3

y > x +2

5 0
3 years ago
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