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vesna_86 [32]
2 years ago
15

(w-x)^2 + 26x; if w = 6 and x = -1

Mathematics
2 answers:
kati45 [8]2 years ago
7 0

Answer:

\boxed{\boxed{\sf 23}}

Step-by-step explanation:

\boxed{\sf Hi\: there!}

\sf (w-x)^2 + 26x

\sf w=6

\sf x=-1

_____________________

→ \sf \left(6-\left(-1\right)\right)^2+26\left(-1\right)

→ \sf 23

»»————- ➴ ————-««

OLga [1]2 years ago
7 0

Answer:

23

Step-by-step explanation:

w = 6

x = - 1

( w - x )^2

= ( 6 - ( - 1 ) )^2

= ( 6 + 1 )^2

= 7^2

= 7 * 7

= 49

26x

= 26 * - 1

= - 26

( w - x )^2 + 26x

= 49 + ( - 26 )

= 49 - 26

= 23

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Answer:

The chance of an average six-sided number cube landing one one number is 1/6, or approximately 16.67%. When rolling a number cube 100 times, the average number of times it lands on any specific number should be fairly close to 16.67.

A 6 being rolled 42 times and 33 times means that it is <em>very likely</em> not to be a standard number cube. Although we cannot know for certain, the chance of this happening is very low.

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Required equation is f(x) = 3/2 x
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4 years ago
Which is the correct answer?
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The answer is H 3

Step-by-step explanation:

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Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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