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vesna_86 [32]
2 years ago
15

(w-x)^2 + 26x; if w = 6 and x = -1

Mathematics
2 answers:
kati45 [8]2 years ago
7 0

Answer:

\boxed{\boxed{\sf 23}}

Step-by-step explanation:

\boxed{\sf Hi\: there!}

\sf (w-x)^2 + 26x

\sf w=6

\sf x=-1

_____________________

→ \sf \left(6-\left(-1\right)\right)^2+26\left(-1\right)

→ \sf 23

»»————- ➴ ————-««

OLga [1]2 years ago
7 0

Answer:

23

Step-by-step explanation:

w = 6

x = - 1

( w - x )^2

= ( 6 - ( - 1 ) )^2

= ( 6 + 1 )^2

= 7^2

= 7 * 7

= 49

26x

= 26 * - 1

= - 26

( w - x )^2 + 26x

= 49 + ( - 26 )

= 49 - 26

= 23

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