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Anastaziya [24]
2 years ago
7

Alice is constructing rectangular prisms to represent buildings in a diorama for her social

Mathematics
1 answer:
Jet001 [13]2 years ago
7 0
L = w + 6

w = l - 6

h = w - 5

h = l - 11

V = lwh

V = l(l - 6)(l - 11)

But V <= 50

therefore,

l^3 - 17l^2 + 66l - 50 <= 0

since all the coefficients add to 0, 1 is a root. Therefore, it can be factored into:

(l-1)(l-8+sqrt(14))(l-8-sqrt(14))<= 0

but at the extremes,

h >= 0

l -11 >= 0

l >= 11

therefore, considering this,

we can see that

11 <= l <= 8 + sqrt(14)

11 - 6 <= l - 6 <= 8 + sqrt(14) - 6

5 <= w <= 2 + sqrt(14)

(In cm)
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Answer:

the answer is c!

Step-by-step explanation:

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Explain why kilobytes and terabytes would not be descriptive measurements for the amount of space on an average USB storage devi
bonufazy [111]

Answer:

The storage capacity of the USB is far greater than Kilobytes, but less than a Terabyte.

Step-by-step explanation:

The USB storage device has a capacity of (8 - 256) GB. This implies that the USB has the capacity to store files size from 8 Gigabytes to 256 Gigabytes.

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Ira Lisetskai [31]
We have that

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7 0
3 years ago
A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

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Thus, the coach should start recruiting players with weight 269.55 pounds or more.

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3 years ago
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stich3 [128]

Answer:

Question number 5

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