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Brilliant_brown [7]
2 years ago
9

The price of a pair of shoes increases from $58 to $61 What is the percent increase to the nearest percent?

Mathematics
2 answers:
marshall27 [118]2 years ago
8 0

Answer:

Step 1: Calculate the change by subtracting old cost ($52) from the new cost ($64)

Step 2: Divide that change by the old cost ($52). You will get a decimal number

Step 3: Convert the decimal number to a percentage by multiplying by 100%

stira [4]2 years ago
3 0

Answer:

23.08

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What is the greatest common factor (gcf) of the numerator and denominator in the rational expression below? 7x+14/2x^2+x-6
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The answer is C. The numerator 7x+14 can be factored as 7(x+2). The denominator 2x^2+2x-6 can be factored as (x+2)(2x-3). The greatest common divisor of 7(x+2) and (x+2)(2x-3) is obviously x+2, which is contained in both of the two expressions.
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3 years ago
5-6n=2n+5 <br>Solve for n
olganol [36]
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7 0
3 years ago
Read 2 more answers
Image point B'(4, -8) was transformed using the translation (x-2, y + 3). What were the coordinates of B?
DaniilM [7]

Answer:

B(6 , -11)

Step-by-step explanation:

(x-2 , y+3)  = (4 , -8)

Compare the x & y co ordinates

x - 2 = 4   ; y + 3 = -8

x = 4 +2  ; y = -8 - 3

x = 6      ; y = -11

B(6 , -11)

8 0
3 years ago
A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe
Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

\omega=\frac{v}{r}    ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}

next, you replace the values of v and r in the equation (1):

\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0
2 years ago
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