There will be 50 gift bags.
The first set of 25 bags
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Because there are 25 thumb drives, the first 25 bags will each have 1 thumb drive.
Also, each bag will have 5 times as many key chains as a thumb drive. Therefore each of the first 25 bags will have
1 thumb drive, 5 key chains.
After the first 25 bags, we have used
25 thumb drives, 5*25 = 125 key chains.
The second set of 25 bags
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We have a total of 200 key chains, so we have 200-125 = 75 key chains left.
Distribute them equally among the remaining 25 bags, so each bag has
75/25 = 3 key chains.
Answer:
25 bags, each with 1 thumb drive and 5 key chains.
Another 25 bags, each with 3 key chains.
Its kinda blurry and I can't read the whole question
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Answer:
308, 398, 421, 433, 570
Step-by-step explanation:
To start we know the smallest is 308 cans, so that is the first class.
Next, it says the range is 262. The range is maximum minus the minimum. Since we know the minimum(308), that means 308 + 262 = 570 and 570 is the maximum or the class with most collected cans.
Then, it says the median or the middle number is 421, the middle number in a class is 3. So, the third class collected a total of 421 cans.
After that, it says the two classes in the three hundred, or the first and second class, has a total of 706 cans. So, if we do 706 - 308 we get the second class. Which collected 398 cans.
Finally, it says the total all the class collected is 2130. So, if we add all the values we have know and subtract it from the total of all the class we get the missing class or the fourth class. So, 308 + 398 + 421 + 570 = 1697, and 2130 -1697 = 433. Which the fourth class.
Least to greatest:
308
398
421
433
570
