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lukranit [14]
3 years ago
8

What is the maximum of the graph? 120 135 n/a 185

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

n/a nuyt

Step-by-step explanation:

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Can't figure out this problem can anyone help if so thank you
Virty [35]

Answer:

10th term of the sequence = 0.537

Step-by-step explanation:

First three terms of the sequence are → 5, 4, \frac{16}{5}..........

Ratio of 2nd and 1st term of the sequence = \frac{4}{5}

Ratio of 3rd and 2nd term of the sequence = \frac{\frac{16}{5} }{4}

                                                                        = \frac{4}{5}

Therefore, ratio between every successive term to the previous term is common.

Common ratio 'r' = \frac{4}{5}

First term of the sequence 'a' = 5

nth term of a geometric sequence = a(r)^n

Therefore, nth term of the given term will be  T_n=5(\frac{4}{5})^n

Now we have to find the 10 term of the given sequence.

For n = 10,

T_{10}=5(\frac{4}{5})^{10}

      = 0.53687

      ≈ 0.537

Therefore, 10th term of the sequence is 0.537

7 0
3 years ago
HELP ASAP
tia_tia [17]
2,700 / 12 = 225
225 / 5 = 45
They can make 45 necklaces.








3 0
4 years ago
What are the factors of m2 – 12m + 20?m – 14 and m – 6m – 10 and m – 2?
AysviL [449]

So for this polynomial, we will be completing the square. Firstly, what two terms have a product of 20m^2 and a sum of -12m? That would be -10m and -2m. Replace -12m with -2m - 10m: m^2-2m-10m+20

Next, factor m^2 - 2m and -10m + 20 separately. Make sure that they have the same quantity inside of the parentheses: m(m-2)-10(m-2)

Now you can rewrite this expression as (m-10)(m-2) . <u>(m - 10) and (m - 2) are your two factors.</u>

4 0
3 years ago
Read 2 more answers
Help quick pleasevngcvvvvv
victus00 [196]
Area of triangle = 0.5(width*height)
4 0
2 years ago
Can someone check my answers and if their wrong explain how to get the correct answer
Charra [1.4K]

Answer: 1. Correct, 2. Incorrect 90° angle not 80° angle answer is 50, 3. Is correct, 4. Is correct

Step-by-step explanation:

8 0
3 years ago
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