Hello there!
a - 15 = 28k
a = 28k + 15
n = 30a + 3 = 30(28k + 15) + 3 = 840k + 453.
The only number that would fit between 1000 and 2000 is 1293.
In short, your answer is 1293.
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Answer:
The correct answer is:

Step-by-step explanation:
We want to solve for the amount of money he pays each month. This is represented by y in the equation. This means we want to isolate y in the equation:
x = t - yz
We first want to subtract t from each side:
x - t = t - yz - t
x - t = -yz
Now we want to cancel the negative sign and z. We can isolate both of these at the same time; divide both sides by -z:
\frac{x-t}{-z} = \frac{-yz}{-z} \\ \\\frac{x-t}{-z}=y
We can divide the numerator by the negative sign; this gives us
\frac{-x+t}{z}=y
The answer is C. 120
The solution can be derived by the formula 6P3.
6P3 = 6 * 5 * 4 = 120
120 different combinations can be made with the condition.
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Standard form is Ax+by= c simply plug your numbers in